Answer:
78.4 m
Explanation:
To obtain the height of the cliff;
We can use the Relation to obtain the final velocity, v
v = u + at
a = acceleration due to gravity = 9.8m/s²
v = 0 + (9.8*4)
v = 0 + 39.2
v = 39.2 m/s
To obtain the Height, S
v² = u² + 2aS
39.2^2 = 0 + 2(9.8)S
39.2^2 = 0 + 19.6S
1536.64 = 19.6S
S = 1536.64 / 19.6
S = 78.4 m
Tension is the force causing the path. It is always directed inward for circular motion. To hit the ceiling you need B. The stopper will travel along the tangent line it was moving when released (when tension goes to 0). This is upward in B so it will keep going up to the ceiling.
The velocity is pointed along the tangent line at all times (parallel to the edge of the circle at any point)
Answer:
34.8 and 55.2º
Explanation:
This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation
The scope equation is
R = v₀² sin 2θ /g
sin 2 θ = R g / v₀²
sin 2 θ = 31 9.8 / 18²
2 θ = sin⁻¹ 0.93765
θ = 34.8º
At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º
Answer:
a) <em>473.33 nm
</em>
<em>b) 568 nm</em><em> and </em><em>406 nm</em>
<em>c) </em>bluish green and blue
Explanation:
a) As the light traverses the layer of oil it first reflects at the front surface of the oil. Here the index of refraction increases from that of air to that of the oil , so a phase change occurs. The light then reflects from the rear surface of oil. The index of refraction increases from that of the oil to that of the glass , so again a phase change occurs. Thus two phase changes occur.
In thin-film interference with 0 or 2 phase changes, condition for constructive interference is:
2t=mλ/n
So:
λ=
2tn/m
<em><u>For m=1</u></em>
λ=1420 nm
<em><u>For m=2</u></em>
λ=710 nm
<em><u>For m=3</u></em>
λ=473.33 nm
<em><u>For m=4</u></em>
λ=355 nm
<em>Thus the only wavelength in the visible spectrum </em><em>(400 - 700 nm)</em><em> that will give constructive interference is </em><em>473.33 nm
</em>
b)
In thin-film interference with 0 or 2 phase changes, condition for destructive interference is:
2t=(m+1/2)λ/n=(2m+1)*λ/2n
so;
λ=4tn/(2m+1)
<em><u>For m=1</u></em>
λ=946.667 nm
<em><u>For m=2</u></em>
λ=568 nm
<em><u>For m=3</u></em>
λ=405.33 nm
<em><u>For m=4</u></em>
λ=315.56 nm
<em>Thus the wavelengths in the visible spectrum (</em><em>400 to 700 nm)</em><em> that will give destructive interference are </em><em>568 nm</em><em> and </em><em>406 nm</em>
<em>c) </em>The color of reflected light is bluish green since the wavelength is 473.3 nm . We know that the colors of reflected and transmitted light are complimentary to each other.Thus the color of transmitted light is blue (due to the combination of wavelengths 568 nm (green) and 406 nm (deep violet).
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