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3 years ago

Think of a real-life example of Boyle's law. Explain it.

Physics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer:

A real-life example of Boyle's law can be seen in a balloon. Air is blown into the balloon; the pressure of that air pushes on the rubber, making the balloon expand. If one end of the balloon is squeezed, making the volume smaller, the pressure inside increased, making the un-squeezed part of the balloon expand out. There is a certain limit to how much the air and gas can be compressed, however, because eventually the pressure becomes so great that it causes the balloon to break.

Explanation:

Hope this helps.

Rina8888 [55]3 years ago

3 0

Air is blown into the balloon; the pressure of that air pushes on the rubber, making the balloon expand.

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Describe a device that transforms thermal energy into another useful form. tes that

spin [16.1K]

Answer: heat engine

Explanation:

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3 years ago

Two sound waves are traveling through the same medium. They have the same amplitude, wavelength, and direction of travel. If the

Sloan [31]

Answer:

Constructive interference

Explanation:

Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.

Let the intensity of waves be I which is same for both

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$I^{2}=I_{1}^{2}+I_{2}^{2}+2I_{1}I_{2}Cos\phi$

where, Ф be the phase difference

So, $I_{R}^{2}=I^{2}+I^{2}+2IICos6\pi$

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4 years ago

A boy can swim 3.0 meter a second in still water while trying to swim directly across a river from west to east, he is pulled by

lana66690 [7]

Answer:

Angle: $48.19^o$

Explanation:

Two-Dimension Motion

When the object is moving in one plane, the velocity, acceleration, and displacement are vectors. Apart from the magnitudes, we also need to find the direction, often expressed as an angle respect to some reference.

Our boy can swim at 3 m/s from west to east in still water and the river he's attempting to cross interacts with him at 2 m/s southwards. The boy will move east and south and will reach the other shore at a certain distance to the south from where he started. It happens because there is a vertical component of his velocity that is not compensated.

To compensate for the vertical component of the boy's speed, he only has to swim at a certain angle east of the north (respect to the shoreline). The goal is to make the boy's y component of his velocity equal to the velocity of the river. The vertical component of the boy's velocity is

$v_b\ cos\alpha$

where $v_b$ is the speed of the boy in still water and $\alpha$ is the angle respect to the shoreline. If the river flows at speed $v_s$ , we now set

$v_b\ cos\alpha=v_s$

$\displaystyle cos\alpha=\frac{v_s}{v_b}=\frac{2}{3}$

$\alpha=48.19^o$

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3 years ago

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pishuonlain [190]

Frequency is the vibration of noise and the vibration determines the pitch, which we depend on to be a pitch or frequency we can hear. If it's too high or too low our ears can't hear it

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3 years ago

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kozerog [31]

Answer:

lol

Explanation:

it was funny

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4 years ago