A computer can show you how it is done and how they got to that solution while a graphing calculator can only show you the solution.
Answer:
10 °C
Explanation:
Applying
q = cm(t₂-t₁)............... Equation 2
Where q = heat energy, c = specific heat of ethanol, m = mass of ethanol, t₁ = initial temperature, t₂ = Final temperature.
Given: c = 2.44 J/g.°C, m = 300 g, q = 14640 J, t₂ = 30°C
Substitute into equation 2 and solve for t₁
14640 = 2.44×300(30-t₁)
14640 = 732(30-t₁)
732(30-t₁) = 14640
(30-t₁) = 14640/732
(30-t₁) = 20
t₁ = 30-20
t₁ = 10 °C
Answer:using Newton third law
Let initial velocity of block be u1=3m/s
Mass of moving block m1 =1kg
Final velocity of block =V
Mass of stationary block m2= 4kg
Since they stick together, their final velocity will be the same.
m1u1 + m2u2=(m1+m2)v
(1*3)+(0*4)=(1+4)v
3=5v
Divide both sides by 5
V=0.6
Final velocity is 0.6m/s
Explanation:
Answer:
Due to application of heat on a saturated solution, the interparticle space increases due to increase in the kinetic energy of the particles which allows more solutes to dissolve in the solution thereby making it unsaturated.
