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1 answer:

podryga [215]3 years ago

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Is this a question or true/false?

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Given data

Initial pressure (P₁): 1 atm (standard pressure)

Initial volume (V₁): 250 mL

Initial temperature (T₁): 273.15 K (standard temperature)

Final pressure (P₂): 0.500 atm

Final volume (V₂): 1500 mL

Final temperature (T₂): ?

We can find the final temperature using the combined gas law.

$\frac{P_1 \times V_1 }{T_1} = \frac{P_2 \times V_2 }{T_2}\\T_2 = \frac{P_2 \times V_2 \times T_1 }{P_1 \times V_1} = \frac{0.500atm \times 1500mL \times 273.15K }{1atm \times 250mL}=819K$

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