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icang [17]
3 years ago
6

18. All of the following are examples of chemical weathering except

Chemistry
2 answers:
jeka943 years ago
7 0
I think d not sure tho but hope it helps
Alexeev081 [22]3 years ago
7 0

Answer:

C

Explanation:

Rocks breaking because of ice.

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Which of the following are considered pure substances?
Helen [10]
B.Elements

Explanation: they cannot be separated
8 0
3 years ago
Limiting Reactants—————-
denis-greek [22]

Answer:

21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

  • Mg: 24.301;
  • O: 15.999.

How many moles of MgO will be produced if Mg is the limiting reactant?

Number of moles of Mg:

\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

7 0
3 years ago
What are two objects from home that have energy and how do I know they have energy?
IRINA_888 [86]
Light bulb -it produces heat and light
toaster - it produces heat and the metal strips glow producing light
7 0
4 years ago
Solution A and solution B are separated by a semipermeable membrane. Solution A contains 1% glucose, solution B contains 5% gluc
Veseljchak [2.6K]

Answer:

Glucose will move from the solution B to the solution A

Explanation:

Given that:

Solution A contains 1% glucose, and,

Solution B contains 5% glucose

Diffusion is the net movement of the substance from the region of the higher concentration to the region of the lower concentration.

Thus, solution B contains more concentration of glucose as compared to solution A. <u>By the process of diffusion, the particle moves from higher concentration to lower concentration and thus, glucose will move from solution B to solution A.</u>

7 0
3 years ago
C2H6 (g) + O2 (g) → CO2 (g) + H2O (g) (not balanced) Determine the number of liters of CO2 formed at STP when 240.0 grams of C2H
Dmitry_Shevchenko [17]

Answer:

13.44dm^3

Explanation:

To calculate this we first need to know the number of mole produced. We will first need to balance the equation to know the theoretical mole ratio.

C2H6 (g) + 3.5O2 (g) → 2CO2 (g) + 3H2O (g)

From the balanced equation, we can deduce that one mole of ethane yielded 2 moles of carbon iv oxide. We use this information to calculate the actual number of moles yielded.

24g were reacted. Now to know the number of moles reacted, we simply divide the mass by the molar mass. The molar mass of ethane is 2(12) +6(1)= 40g/mol

The number of moles is thus 24/40 = 0.6 moles

Like we said earlier, one mole yielded 2 moles of carbon iv oxide, hence, 0.6 moles will yield 0.6 * 2 = 0.12 moles of carbon iv oxide.

Now, at stp, one mole of a gas occupies a volume of 22.4dm^3 thus, 0.6 mole will occupy 0.6 * 22.4 = 13.44dm^3

8 0
3 years ago
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