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3 years ago

Which graph shows a triangle and its reflection image across the x-axis?

Mathematics

2 answers:

Sav [38]3 years ago

8 0

What are the options

natita [175]3 years ago

3 0

D is the correct answer

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I will give brainliest just please help

prisoha [69]

Answer:

you can be on a call back at your the one in your the one in your office at it and

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3 years ago

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What is the result when the number 32 is increased by 25%?

natulia [17]

Answer:

32, percentage increaced by 25% =40

Step-by-step explanation:

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3 years ago

What is the answer of 12x - 6 = 54

Bogdan [553]

Answer:

x = 5

Step-by-step explanation:

12x - 6 + 6 = 54 + 6

12x = 60

12/12 = 60/12

X = 5

7 0

1 year ago

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A polygon is shown on the graph:

iren [92.7K]

so translation means that the points are moving on the graph

so the shape is moving down three then left two

it doesn’t change the shape in any way it just moves the shape

so all the sides and angles are the same

so the polygon is completely congruent with the premise and image since the shape didn’t change

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3 years ago

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MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago