Question

Determine a submarines acceleration if it's initial velocity is 9.0 m/s and it travels 1.54 km in 2 min

Answer 1

$acceleration=\frac{\Delta v}{\Delta t}\\\\ \Delta t=2min=120s\\\\s=1,54km=1540m\\\\ acceleration=\frac{v_{f}-v_{i}}{\Delta t}\\\\ \Delta v=\frac{s}{t}\\ v_{f}-v_{i}=\frac{s}{t}\\ v_{f}=\frac{1540}{120}+9=21,83\frac{m}{s}\\\\ accleration=\frac{21,83-9}{120}=\frac{12,83}{120}=\boxed{0,107\frac{m}{s}}$