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3 years ago

Determine a submarines acceleration if it's initial velocity is 9.0 m/s and it travels 1.54 km in 2 min

1 answer:

6 0

$acceleration=\frac{\Delta v}{\Delta t}\\\\ \Delta t=2min=120s\\\\s=1,54km=1540m\\\\
acceleration=\frac{v_{f}-v_{i}}{\Delta t}\\\\
\Delta v=\frac{s}{t}\\
v_{f}-v_{i}=\frac{s}{t}\\
v_{f}=\frac{1540}{120}+9=21,83\frac{m}{s}\\\\
accleration=\frac{21,83-9}{120}=\frac{12,83}{120}=\boxed{0,107\frac{m}{s}}$

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A student new to the study of hearing wanted to determine the ability of listeners to determine the difference in the duration o

denis23 [38]

Answer:

No, duration is not the sole reason.

Explanation:

The frequency is reciprocal of time period, so we can calculate the frequency differences between the waves as, (The frequency will not match with the actual waves frequency, since here the time for observing the wave is different)

Δf₁ = 1/5 - 1/20 = 0.15 Hz

Δf₂ = 1/200 - 1/400 = 2.5 x 10⁻³ Hz

So, the person will be able to differentiate between the waves which are farther apart. The duration of the individual tones is also important, since as the duration of the tones decreases, the number of frequencies in the wave increases (Fourier Transform), whereas a longer duration tone, has lesser number of frequencies.

One more reason is that the 200 msec and 400 msec duration waves are in frequency region of 1-5 Hz which cannot be heard by Humans.

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3 years ago

B. In the vicinity of Earth’s orbit around the Sun, the energy intensity of sunlight is about 1600 W/m2 . What is the approximat

Vera_Pavlovna [14]

Answer:

1097.8 V/m

Explanation:

The equation that relates the intensity of an electromagnetic wave with the magnitude of the electric field is:

$I=\frac{1}{2}c\epsilon_0 E^2$

where

c is the speed of light

$\epsilon_0$ is the vacuum permittivity

E is the peak magnitude of the electric field

In this problem, we know the intensity:

I = 1600 W/m^2

So we can rearrange the formula to find E:

$E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1600 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=1097.8 V/m$

4 0

3 years ago

What is the answer ?

Fofino [41]

P= mv
p=(.5)(20)
p=10 kg/ms

7 0

3 years ago

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh

frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

$y\propto x^{1.25}$

$y=kx^{1.25}$

$k=\dfrac{y}{x^{1.25}}$

Put the value into the formula

$k=\dfrac{1.8}{1.1^{1.25}}$

$k=1.5978$

We need to calculate the crab weight

$y=kx^{1.25}$

Here, x = 0.85 g

Put the value into the formula

$y=1.5978\times(0.85)^{1.25}$

$y=1.3040\ gram$

Hence, The weight of body is 1.3040 gram.

7 0

4 years ago

A car traveling at 40 ft/sec decelerates at a constant 5 feet per second per second. how many feet does the car travel before co

Tema [17]

<span>This problem is solved by the equation of motion: x = x0 + v0*t + 1/2*a*t^2, Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t: v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a -- > 40/5 = 8 seconds to stop. In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft. Answer: The car travels 160 ft.</span>

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3 years ago