How much work does a motor do as it lifts a 675-kilogram elevator from a height of 15 meters to a height of 35 meters?

1 answer:

3 0

Work is defined as Force x Distance

W = Fd

so (675kg)(9.8m/s^2) = 6615 N

d = 35-15 = 20m

so

W = Fd
(6615N)(20m)

132,300 J = W

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