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cupoosta [38]
3 years ago
7

A stable, binary ionic compound exists where the cation (A) has a charge twice in magnitude than that of the anion (X). What wou

ld be the correct formula for this compound?
Physics
2 answers:
garri49 [273]3 years ago
8 0
Since the cation (A) has a charge twice in magnitude than that of the anion (X), you can say the magnitude of the charge of the cation is 2c, while the magnitude of the charge of the anion is c. 

Also remember that cations are positive ions, so the charge would be +2c, and that anions are negative ions, so the charge would be -c.

A binary ionic compound of A and X would have to have a net charge of zero. If A has a +2c charge, you would need two X anions to balance out every A cation, so the formula would be:
A_{c}X_{2c}

The simplest formula would be AX_{2}.
ki77a [65]3 years ago
4 0
The formula is AX^2       fbdfdxv
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Snezhnost [94]
We can solve the problem by using Snell's law, which states 
n_i \sin \theta_i = n_r \sin \theta_r
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n_r is the refractive index of the second medium
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In our problem, n_i=1.00 (refractive index of air), \theta_i = 28.0^{\circ} and n_r=1.63 (refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
\sin \theta_r =  \frac{n_i}{n_r}  \sin \theta_r =  \frac{1.00}{1.63}  \sin 28.0^{\circ} = 0.288
From which we find
\theta_r = \arcsin (0.288)=16.7^{\circ}
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Answer:

Explanation:

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