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Anna [14]
3 years ago
13

A student new to the study of hearing wanted to determine the ability of listeners to determine the difference in the duration o

f two tones as a means to study temporal discrimination. He asked listeners to discriminate between a tone of 5 mse duration and one of 20 msec duration, and in another condition between a tone of 200 msec duration and one of 400 msec duration. He found that the listeners could detect the difference between the 5 and 20 msec tones better than they could differentiate between the 200 and 400 msec tones. Does this mean that the duration is the only reason that the difference thresholds are different for the short duration tones as compared to the long duration tones? (hint: a short duration stimulus like a click has a spectrum made up of many frequencies). Path: p Words: 0
Physics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

No, duration is not the sole reason.

Explanation:

The frequency is reciprocal of time period, so we can calculate the frequency differences between the waves as, (The frequency will not match with the actual waves frequency, since here the time for observing the wave is different)

Δf₁ = 1/5 - 1/20 = 0.15 Hz

Δf₂ = 1/200 - 1/400 = 2.5 x 10⁻³ Hz

So, the person will be able to differentiate between the waves which are farther apart. The duration of the individual tones is also important, since as the duration of the tones decreases, the number of frequencies in the wave increases (Fourier Transform), whereas a longer duration tone, has lesser number of frequencies.

One more reason is that the 200 msec and 400 msec duration waves are in frequency region of 1-5 Hz which cannot be heard by Humans.

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Answer:

a cricket stamp

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4 0
3 years ago
What an object is placed 8 mm from a concave spherical mirror a clear image can be projected on the screen 16 mm in front of me
alexgriva [62]

Concept: The magnification of spherical mirror can be defined by two ways.

(i) In terms of the height of the object and image.

The magnification of the spherical mirror is defined as the ratio of the height of the image'h_{i}' to the height of the object 'h_{o}'. It is denoted by letter 'm'.

Mathematically, it can be written as

m= \frac{h_{i}}{h_{o}}   ------------(1)

(ii) In terms of the object's and image's distances.

The magnification of the spherical mirror is defined as the negative ratio of the image distance'd_{i}' to the object distance 'd_{o}'.

Mathematically, it can be written as

m= - \frac{d_{i}}{d_{o}}   ------------(2)

Now, from equation (1) and (2) we have,

m = \frac{h_{i}}{h_{o}}   = -  \frac{d_{i}}{d_{o}}  -----------(3)

Given: Spherical Concave Mirror,

We will consider positive sign for object's and image's distance because both are in front of the mirror.

Object distance (d_{o}) = + 8 mm.

Image distance (d_{i}) = + 16 mm

Object's height (h_{o}) = + 4 mm

Image's height (h_{i}) =?

Now, apply equation (3)

\frac{h_{i}}{h_{o}}   = - \frac{d_{i}}{d_{o}}

Or,   \frac{h_{i}}{4 mm}   = - \frac{+16 mm}{+8 mm}

Or, hi = - 8 mm

Here; negative sign means, the image will be inverted.

The image's height will be 8 mm.

4 0
3 years ago
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
Bas_tet [7]

Answer:

Explanation:

Total momentum of the system before the collision

.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left

If v be the velocity of the stuck pucks

momentum after the collision = 2 v

Applying conservation of momentum

2 v = -  .75

v =  - .375 m /s

Let after the collision v be the velocity of .5 kg puck

total momentum after the collision

.5 v + 1.5 x .231 = .5v +.3465

Applying conservation of momentum law

.5 v +.3465 = - .75

v = - 2.193 m/s

2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.

Kinetic energy before the collision

= 2.25 + 1.6875

=3.9375 J

kinetic energy after the collision

= .04 + 1.2 =1.24 J

So kinetic energy is not conserved . Hence collision is not elastic.

3 ) Change in the momentum of .5 kg

1.5 - (-1.0965 )

= 2.5965

Average force applied = change in momentum / time

= 2.5965 / 25 x 10⁻³

= 103.86 N

5 0
3 years ago
Is the process of changing from one phase of matter to another a physical change or a chemical change? Explain why. please asap
Andreas93 [3]

The process of changing from one phase  of matter to another is a physical matter.

7 0
3 years ago
during convection, hot material _____ (expands & sinks, cools & rises, expands & rises, deflates & rises) then m
Lady bird [3.3K]

Answer:

During convection, hot material expands & rises then moves to the side and cools & sinks. this circular pattern is called a convection current.

Explanation:

Convection is one of the three methods of transfer of heat. It occurs only in fluids (liquids or gases).

Convection occurs when there is a source of heat that heats a fluid, such as in a boiling pot of water. The water which is on the bottom of the pot becomes warmer before than the water at the top (because it is closer to the flame), and so it becomes less dense: for this reason, it expands and it becomes rising. On the contrary, the water on top is colder, so it is more dense and starts sinking, replacing the warmer water. As the new part of water gets warmer, it starts rising, and so the process is continuously repeated. This circular current is called convection current.

4 0
3 years ago
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