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Anna [14]
3 years ago
13

A student new to the study of hearing wanted to determine the ability of listeners to determine the difference in the duration o

f two tones as a means to study temporal discrimination. He asked listeners to discriminate between a tone of 5 mse duration and one of 20 msec duration, and in another condition between a tone of 200 msec duration and one of 400 msec duration. He found that the listeners could detect the difference between the 5 and 20 msec tones better than they could differentiate between the 200 and 400 msec tones. Does this mean that the duration is the only reason that the difference thresholds are different for the short duration tones as compared to the long duration tones? (hint: a short duration stimulus like a click has a spectrum made up of many frequencies). Path: p Words: 0
Physics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

No, duration is not the sole reason.

Explanation:

The frequency is reciprocal of time period, so we can calculate the frequency differences between the waves as, (The frequency will not match with the actual waves frequency, since here the time for observing the wave is different)

Δf₁ = 1/5 - 1/20 = 0.15 Hz

Δf₂ = 1/200 - 1/400 = 2.5 x 10⁻³ Hz

So, the person will be able to differentiate between the waves which are farther apart. The duration of the individual tones is also important, since as the duration of the tones decreases, the number of frequencies in the wave increases (Fourier Transform), whereas a longer duration tone, has lesser number of frequencies.

One more reason is that the 200 msec and 400 msec duration waves are in frequency region of 1-5 Hz which cannot be heard by Humans.

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3 years ago
The 10 kg dancer leaps into the air with an initial velocity of 5 m/s at angle of 45° from the floor. How far will she travel in
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Answer:

2.55 m

Explanation:

The motion of the dancer is the motion of a projectile, which consists of 2 independent motions:

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The horizontal range of a projectile can be found by using the equations of motions along the two directions, and it is given by:

d=\frac{v^2 sin(2\theta)}{g}

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For the dancer in this problem, we have:

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Therefore, the horizontal range is:

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5 0
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Answer:

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Explanation:

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Answer:Voltage

Explanation:

Voltage stays the same at any point in a parallel circuit

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