<span>(a)
Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get:
18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component.
(b)
To much the same end do we derive the vertical component:
18.0*sin37.5 = v_y = 10.96 ms^-1
Which we then divide by acceleration, a_y, to derive the time till maximal displacement,
10.96/9.8 = 1.12 s
Finally, doubling this value should yield the particle's total time with r_y > 0
<span>2.24 s
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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0.120L + 2.345L = 2.465L = 4 significant figures in the answer
Answer:
Explanation:
Given that,
The mass of a golf ball, m = 40 g = 0.04 kg
Its angular velocity, 
The radius of the sphere is 2.5 cm or 0.025 m
We need to find the magnitude of the angular momentum of the ball. It is given by the formula as follows:
Where I is moment of inertia
For sphere, 
So, the magnitude of the angular momentum of the sphere is 
.
Answer:
12 kgm²
Explanation:
here angular acceleration = 10rad/sec²
torque= 120Nm
moment of inertia=?
we know,
torque= angular acceleration× moment of Inertia
or, moment of inertia = torque/angular acceleration
= 120/10
= 12kgm²
