Answer:
(A) E = 2.633 * 10^19 N/C
(B) E = 1.096 * 10^13 N/C
(C) E = -1.096 * 10^13 N/C
Explanation:
Parameters given:
Number of protons, N = 92
Radius of Uranium nucleus = 7.4 * 10^-15 m
Electronic charge, ẹ = 1.6023 * 10^-19 C
Electric field at a point R due to a charge Q is given as
E = (k*Q) / (R^2)
Where k =Coulombs constant
(A) Since there are 92protons,the total Electric field due to the protons will be:
E = (k*e*N) / (R * R)
E = (9 * 10^9 * 92 * 1.6023 * 10^-19) / (7.4 * 10^-15)^2
E = 2.633 * 10^19 N/C
(B) At the position of the electrons, R = 1.1 * 10^-10m. Therefore, Electric field will be:
E = (9 * 10^9 * 92 * 1.6023 * 10^-19) / (1.1 * 10^-10)^2
E = 1.096 * 10^13 N/C
(C) There are 92 electrons in the Uranium atom and electrons have a charge - e, hence, the Electric field due to the electrons at the nucleus will be:
E = -(k*e*N) / (R * R)
E = -(9 * 10^9 * 92 * 1.6023 * 10^-19) / (1.1 * 10^-10)^2
E = -1.096 * 10^13 N/C
