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alina1380 [7]
3 years ago
14

Use the mass and density data to calculate the volume of corn syrup to the nearest tenth.

Physics
2 answers:
Bas_tet [7]3 years ago
6 0

Answer:

79.1 ml

Explanation:

The density of an object is defined as the ratio of mass of the object to the volume of the object.

Volume of corn syrup = mass of corn syrup x density of corn syrup

Volume of corn syrup = 57.3 x 1.38 = 79.1 ml

Nataly [62]3 years ago
4 0
41.5 is the answer that i got. hope this helps!

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B) I just took the test and put D but it gave me the wrong answer. It told me it was B.

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A car weighing 14,700 N is speeding down a highway with a velocity of 99 km/h. What is the
tankabanditka [31]

Answer: 148348.6239 kg•m/s

Explanation: Firstly, we need to convert the 14700 N into kilograms, and to do so, use the formula net force is equal to mass times acceleration and rearrange the formula to find mass like shown below...

F = ma

F/a = m

14700/9.81 = 1498.470948 kg, this is your mass

Now that we convert it into kilograms, plug all the numbers into the variable of the momentum formula.

Momentum formula is P = mass x velocity

Like this:

P = 1498.470948 x 99

p = 148348.6239 kg•m/s.

I believe that is your answer, hope that helps you even a bit out.

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7 0
2 years ago
Many of the male characteristics come from which reproductive hormone?
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The atomic mass of an atom do not contain electrons because
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Answer:

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7 0
3 years ago
A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider t
Oduvanchick [21]

Answer:

just before landing the ground

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Let the velocity of projection is u and the angle of projection is 30°.

Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.

initial horizontal component of velocity, ux = u Cos 30

initial vertical component of velocity, uy = u Sin 30

Time of flight is given by

T = \frac{2u Sin\theta }{g}

Final horizontal component of velocity, vx = ux = u Cos 30

Let vy is teh final vertical component of velocity.

Use first equation of motion

vy = uy - gT

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v_{y}=u Sin 30 - 2u Sin 30

vy = - u Sin 30

The magnitude of final velocity is given by

v = \sqrt{v_{x}^{2}+v_{y}^{2}}

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v = u

Thus, the velocity is same as it just reaches the ground.

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3 years ago
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