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padilas [110]
4 years ago
8

The difference between a nuclear weapon detonation and a conventional explosion is __________.

Physics
1 answer:
viktelen [127]4 years ago
3 0
Fission. In a nuclear explosion the atom nucleus splits, not in a conventional explosion
You might be interested in
If a net horizontal force of 0.8 N is applied to a toy whose mass is 1.2 kg what acceleration is produced?
julia-pushkina [17]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{0.8}{1.2}   \\  = 0.666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

6 0
3 years ago
Juliana walks 45 meters East, 45 meters south and 45 meters north. What is her resultant displacement?
katrin2010 [14]

Her resultant displacement is (45 Meters East.)

She originally walks 45 meters east, then she goes south 45 meters, then north 45 meters.  The south and north placements  just make her go back to where her previous placements were before them. Making her 45 meters east.

6 0
3 years ago
An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is neg
Serjik [45]

Given that,

Horizontal velocity of the object, v = 20 m/s

Height of the cliff, h = 125 m

We need to find the time that it takes the object to fall to the ground from the cliff is most nearly. It can be calculated using second equation of motion. Let us consider that the initial speed of the object is 0. So,

h=ut+\dfrac{1}{2}at^2

Here, a = g and u = 0

h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 125}{10}} \\\\t=5\ s

So, the object will take 5 seconds to fall to the ground from the cliff.

5 0
3 years ago
The distance between Saturn and the sun is approximately 8.9 × 10^8 mi. The speed of light is approximately 1.9 × 10^5 miles per
lbvjy [14]

khata ko xoro branly branly is fool

7 0
3 years ago
Two identical 0.50-kg carts, each 0.10 m long, are at rest on a low-friction track and are connected by a spring that is initial
Keith_Richards [23]

Answer:

The system's kinetic energy changes by 3.6 J

Explanation:

The given parameters are;

The number of cart = 2

The mass of each cart = 0.5kg

The initial length of the spring = 0.50 m

The final length of the spring =T0.3 m

The change in position of the first cart = 0.6 m

The energy given to the first cart = Work done by the force = Force × Displacement

The initial kinetic energy of the two cart moving together = Energy given to the first cart = 6.0 × 0.2 = 1.2J

The kinetic energy given to the two cart combined = The applied force × The total displacement of the two cart as they move together

The kinetic energy given to the two cart combined = 6.0 × (0.6 - 0.2)

The kinetic energy given to the two cart combined = 6.0 × 0.4 = 2.4 J

The total kinetic energy given to the two cart = 1.2 + 2.4 = 3.6 J

The total kinetic energy given to the two cart = 3.6 J

The system's kinetic energy changes by 3.6 J.

8 0
3 years ago
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