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padilas [110]
3 years ago
8

The difference between a nuclear weapon detonation and a conventional explosion is __________.

Physics
1 answer:
viktelen [127]3 years ago
3 0
Fission. In a nuclear explosion the atom nucleus splits, not in a conventional explosion
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How does the​ long-run equilibrium for a monopolistically competitive market differ from the​ long-run equilibrium for a perfect
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The main difference between monopolistic competition and perfect competitive market are given bellow

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Markup over marginal cost:   the another distinction between flawless challenge and monopolistic challenge is the connection among cost and minor expense. At an aggressive firm consistently cost equivalents negligible expense. Where as, in monopolistically aggressive firm, cost surpasses minimal expense becouse the firm consistently have some market control.

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The phrase terminal velocity can best be defined as
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None of these are a good definition; a good definition would be "the maximum velocity that an object can fall at." however the best answer out go those is c. the constant velocity of some falling objects. 
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Which best describes protein
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Which two pieces of evidence most directly support the idea that the universe is expanding from one original point?
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Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distan
lilavasa [31]

The distance between the first and second-order dark fringe is 0.441 m.

Diffraction of a single slit:

When the light wave passes through a single slit of width which is comparable to the wavelength of the light, then the light wave bends at the edges of the slit. This is called diffraction.

Note: It is assumed that the slit is 3*10^(-3) mm wide. 1 nm = 10^(-9) m and 1mm = 10^(-3) m.

The dark fringes are obtained at the position which satisfies the equation,

d*sinθ = mλ

where d is the slit width, λ is the wavelength of the wave, θ is the angle of diffraction and m denotes the order of the dark fringe.

For first order fringe (m=1), the angle of diffraction θ₁ is,

d*sinθ₁ = λ

sinθ₁ =λ/d

Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.

sinθ₁ =(590 nm)/(3*10^(-3) mm)

sinθ₁ =(590*10^(-9))/ (3*10^(-3)*10^(-3) m)

sinθ₁ =0.196

θ₁ =11.03 degree

Similarly, for second-order fringe (m=2), the angle of diffraction θ₂ is,

d*sinθ₂= 2λ

sinθ₂ =2λ/d

Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.

sinθ₂ =(2*590 nm)/(3*10^(-3) mm)

sinθ₂ =(2*590*10^(-9))/ (3*10^(-3)*10^(-3) m)

sinθ₂ =0.393

θ₂ =23.14 degree

From geometry, the positions x₁ and x₂ of the first and second-order dark fringe from the center of the screen are x₁=Dtanθ₁ and x₂= Dtanθ₂ where D is the distance of the screen from the slit. The distance s between the first-order and second-order dark fringe is then given by,

s=D(tanθ₂-tanθ₁)

Substitute D=1.90 m, θ₁=11.03 degree, and θ₂=23.14 degree in this equation and solve it.

s=1.90*(tan(23.14)-tan(11.03))

s=1.90*(0.427-0.195)

s=0.441 m

Learn more about diffraction here:

brainly.com/question/12290582

#SPJ4

4 0
1 year ago
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