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Anettt [7]
3 years ago
6

A 10,000 N piano is dropped from the top of a building. When the piano reaches terminal speed…

Physics
1 answer:
wel3 years ago
7 0

a). When the piano reaches terminal speed, it is no longer accelerating,
so the net force on it must be <em>zero</em>.

b). If the net force on the piano is zero, the upward force of air resistance on it
must be exactly equal to the downward force of gravity ... <em>10,000 N</em>.


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20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?
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Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
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If a coin has a mass of 29.34g and drops from a height of 14.7 meters, what is its loss in gravitational potential energy? Show
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7 0
3 years ago
A long, thin solenoid has 450 turns per meter and a radius of 1.06 . The current in the solenoid is increasing at a uniform rate
kirill115 [55]

Answer:9.34 A/s

Explanation:

Given

radius of solenoid R=1.06 m

Emf induced E=8.50\times 10^{-6} V/m

no of turns per meter n=450

we know Induced EMF is given by

\int Edl=-\frac{\mathrm{d} \phi}{\mathrm{d} t}=-\frac{\mathrm{d} B}{\mathrm{d} t}A

Magnetic Field is given by

B=\mu _0ni

thus \frac{\mathrm{d} B}{\mathrm{d} t}=-\mu _0n\frac{\mathrm{d} i}{\mathrm{d} t}

Area of cross-section

A=\pi R^2 where

solving integration we get

E.\cdot 2\pi r=\mu _0n\frac{\mathrm{d} i}{\mathrm{d} t}\pi R^2

where r=distance from axis

R=radius of Solenoid

\frac{\mathrm{d} i}{\mathrm{d} t}=\frac{Er}{\mu _0nR^2}

\frac{\mathrm{d} i}{\mathrm{d} t}=\frac{8.50\times 10^{-6}\times 3.49\times 10^{-2}}{4\pi \times 10^{-7}\times 450\times 1.06^2}

\frac{\mathrm{d} i}{\mathrm{d} t}=9.34 A/s

4 0
3 years ago
Which type of mechanical wave is a sound wave?
kykrilka [37]
It’s A.Longitudinal. Tell me if I’m right
4 0
3 years ago
Read 2 more answers
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