Answer:
Distance, d = 0.1 m
It is given that,
Initial velocity of meson,
Finally, the meson is coming to rest v = 0
Acceleration of the meson, (opposite to initial velocity)
Using third equation of motion as :
s is the distance the meson travelled before coming to rest.
So,
s = 0.1 m
The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.
The mechanical advantage is the factor by which
the machine multiplies the input force.
If the MA is 3 and the input force is 630N, then
the output force is
(3) x (630N) = 1,890N
Answer: 15 m/s2
Explanation: I hope this helps or right because I learned this a few months ago
Answer:
what is your question because I seem to not see a question in this question....
