Answer:
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Explanation:
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Each capacitor carry the same charge 'q'.
Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:
= V₁ +V₂ +V₃
This voltage may also be calculated using capacitance and charge;
V = Q/ C
= V₁ +V₂ +V₃
Provided that the total charge is 'q', hence the total voltage can be expressed as:
= (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)
Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.
Learn more about the capacitor here:
brainly.com/question/17176550
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Answer:
Image distance of apple=-6.7 cm
Magnification of apple=0.33
Explanation:
We are given that an apple is placed 20.cm in front of a diverging lens.
Object distance=u=-20 cm
Focal length=f=-10 cm
Because focal length of diverging lens is negative.
We have to find the image distance and magnification of the apple.
Lens formula
![\frac{1}{f}=\frac{1}{v}-\frac{1}{u}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bv%7D-%5Cfrac%7B1%7D%7Bu%7D)
Substitute the values then we get
![-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B10%7D%3D%5Cfrac%7B1%7D%7Bv%7D%2B%5Cfrac%7B1%7D%7B20%7D)
![\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D%3D-%5Cfrac%7B1%7D%7B10%7D-%5Cfrac%7B1%7D%7B20%7D)
![\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D%3D%5Cfrac%7B-2-1%7D%7B20%7D%3D-%5Cfrac%7B3%7D%7B20%7D)
![v=-\frac{20}{3}=-6.7 cm](https://tex.z-dn.net/?f=v%3D-%5Cfrac%7B20%7D%7B3%7D%3D-6.7%20cm)
Image distance of apple=-6.7 cm
Magnification=m=![\frac{v}{u}=\frac{-\frac{20}{3}}{-20}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Bu%7D%3D%5Cfrac%7B-%5Cfrac%7B20%7D%7B3%7D%7D%7B-20%7D)
Magnification of apple=![\frac{1}{3}=0.33](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%3D0.33)
Hence, the magnification of apple=0.33
Explanation:
It is given that,
Speed of the jet airplane with respect to air,
If the wind at the airliner’s cruise altitude is blowing at 100 km/h from west to east, ![v_{AG}= 100\ km/h](https://tex.z-dn.net/?f=v_%7BAG%7D%3D%20100%5C%20km%2Fh)
(A) Let
is the speed of the airliner relative to the ground if the airplane is flying from west to east,
![v_{PG}=900-100=800\ km/h](https://tex.z-dn.net/?f=v_%7BPG%7D%3D900-100%3D800%5C%20km%2Fh)
(B) Let
is the speed of the airliner relative to the ground if the airplane is flying from east to west,
![v'_{PG}=900+100=1000\ km/h](https://tex.z-dn.net/?f=v%27_%7BPG%7D%3D900%2B100%3D1000%5C%20km%2Fh)
Hence, this is the required solution.
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