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3 years ago

ASAP PLZ HELP 1 EASY QUESTION HELP :/

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

If 2 triangles are similar, the ratio of one side of the triangle to the corresponding side of the other is always same for all 3 sides.
We can make use of this rule to calculate the length of sides.
From the image,
3 / 15 = 6 / x
Simplify,
1 / 5 = 6 / x
Use cross method to solve this.
5 x 6 = 1 x x
X = 30
Therefore the length of x is 30ft., A.

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R/3 + 5 < 8<br><br> please help

Feliz [49]

Answer:

r<9

Step-by-step explanation:

r/3 + 5 < 8

Subtract 5 from each side

r/3 + 5-5 < 8-5

r/3 < 3

Multiply each side by 3

r/3 *3 <3*3

r<9

3 0

3 years ago

Help please it is math

Alex

7x+100+68.25 Let me know if you want me to explain it to you

8 0

3 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago

Evaluate 8 + 3e when e = 2.<br> Need the Answer

alexandr402 [8]

Answer:

The answer is 14

Step-by-step explanation:

e=2

Substitute 2 in for e

8 + 3(2)

Solve

6 0

3 years ago

sally gave her brother 3.95 in quarters and dimes. if the number of quarters is 6 more then the number of dimes, how many quarte

iragen [17]

Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)

(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)

(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)

(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.

7 0

3 years ago