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ki77a [65]
2 years ago
6

If you could travel 900 meters in 55 seconds, what is your speed? (Answer in details=brainliest)

Physics
1 answer:
Alika [10]2 years ago
7 0

Answer:

<em>The </em><em>rate </em><em>of </em><em>change </em><em>of </em><em>distance</em><em> </em><em>is </em><em>called </em><em><u>speed </u></em><em>it </em><em>can </em><em>also </em><em>be </em><em>defined</em><em> </em><em>as </em><em>distance</em><em> </em><em>travelled</em><em> </em><em>per </em><em>unit </em><em>time,</em><em>from </em><em>these </em><em>definition</em><em> </em><em>you </em><em>can </em><em>tell </em><em>that </em><em>the </em><em>formula</em><em> </em><em>will </em><em>be </em>

<em>speed=</em><em>distance</em><em>/</em><em>time</em>

<em>in </em><em>this </em><em>question</em><em> </em><em>the </em><em>distance</em><em> </em><em>is </em><em>9</em><em>0</em><em>0</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em> </em><em>and </em><em>the </em><em>time </em><em>is </em><em>5</em><em>5</em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em>s</em><em> </em><em>therefore</em><em> </em><em>the </em><em>speed </em><em>will </em><em>be:</em>

<em>s=</em><em>9</em><em>0</em><em>0</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em>/</em><em>5</em><em>5</em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em>s</em>

<em>=</em><em>1</em><em>6</em><em>.</em><em>3</em><em>6</em><em>m</em><em>/</em><em>s</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

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Find the height of the coconut from the ground at the moment the arrow hit it.
Wewaii [24]

Answer:

v = u + at \\ 0 = 45 \sin(20)  -  9.81 \times t  \\ t = 1.56s

7 0
2 years ago
1. °C= (°F-32) X 5/9. what will be the answer?
aleksley [76]

Answer:

F=9/5(°C)+32

Explanation:

Lets take an example

  • Take 25°C

\\ \sf\longmapsto \dfrac{9}{5}(25)+32

\\ \sf\longmapsto 9(5)+32

\\ \sf\longmapsto 45+32

\\ \sf\longmapsto 77°F

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3 years ago
An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
3 years ago
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Answer:

it is reduced four times.

Explanation:

By definition, the electric field is the force per unit charge created by a charge distribution.

If the charge creating the field is a point charge, the force exerted by it on a test charge, must obey Coulomb´s Law, so, it must be inversely proportional to the square of the distance between the charges.

So, if the distance increases twice, as the force is inversely proportional to the square of the distance, and the square of 2 is 4, this means that the magnitude of the force exerted on the test charge must be 4 times smaller.

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Answer:

i font know ewan madaling sabihin yan

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