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ki77a [65]
3 years ago
6

If you could travel 900 meters in 55 seconds, what is your speed? (Answer in details=brainliest)

Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

<em>The </em><em>rate </em><em>of </em><em>change </em><em>of </em><em>distance</em><em> </em><em>is </em><em>called </em><em><u>speed </u></em><em>it </em><em>can </em><em>also </em><em>be </em><em>defined</em><em> </em><em>as </em><em>distance</em><em> </em><em>travelled</em><em> </em><em>per </em><em>unit </em><em>time,</em><em>from </em><em>these </em><em>definition</em><em> </em><em>you </em><em>can </em><em>tell </em><em>that </em><em>the </em><em>formula</em><em> </em><em>will </em><em>be </em>

<em>speed=</em><em>distance</em><em>/</em><em>time</em>

<em>in </em><em>this </em><em>question</em><em> </em><em>the </em><em>distance</em><em> </em><em>is </em><em>9</em><em>0</em><em>0</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em> </em><em>and </em><em>the </em><em>time </em><em>is </em><em>5</em><em>5</em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em>s</em><em> </em><em>therefore</em><em> </em><em>the </em><em>speed </em><em>will </em><em>be:</em>

<em>s=</em><em>9</em><em>0</em><em>0</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em>/</em><em>5</em><em>5</em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em><em>s</em>

<em>=</em><em>1</em><em>6</em><em>.</em><em>3</em><em>6</em><em>m</em><em>/</em><em>s</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

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By replacing all known variables:

\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}

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