A mole of an ideal gas expands from a initial volume of 7 l to 15 l at a constant temperature of 340 k. how much work is done by
1 answer:
You might be interested in
Answer:0.3
Explanation:
Given
velocity of car=15 m/s
truck brought to halt in a distance of 38 m
We know
Final velocity (v)=0
(deceleration)
Therefore minimum coefficient of friction \mu will be
The correct answer is: Option (3) 9.8 N/kg
Explanation:
According to Newton's Law of Gravitation:
--- (1)
Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
m = Mass of the body = 2 kg
M = Mass of the Earth = 5.972 × 10²⁴ kg
R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m
Plug in the values in (1):
(1)=>
Now that we have force strength at the location, we can use:
Force = mass * gravitational-field-strength
Plug in the values:
19.63 = 2.0 * gravitational-field-strength
gravitational-field-strength = 19.63/2 = 9.82 N/kg
Hence the correct answer is Option (3) 9.8 N/kg