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USPshnik [31]
3 years ago
7

A 750 kg National Geographic Drone is rising vertically up into the atmosphere at constant speed. The lift force pushing it upwa

rd is 125% of its weight. The drone reaches the cruising speed almost immediately. It takes 25 seconds for the drone to reach a height of 250m starting from the surface.
a. What is the mechanical energy of the drone at the surface?
b. What is the mechanical energy of the drone at the 150 m height?
c. Is the mechanical energy of the drone conserved, increased, or decreased. Explain your choice.
d. What is the work done by each force acting on the drone?
Physics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

a. 0

b. 1.103625 MJ

c. Conserved

d. 1.103625/n MJ where n = The number of forces

Explanation:

The mass of the drone, m = 750 kg

The upward lift force = 125% of the weight of the drone

The time it takes the drone to reach a height of 250 m = 25 seconds

a. The mechanical energy = The kinetic energy + Potential energy

Therefore, given that the drone stars motion from the surface and was initially at rest, the mechanical energy at the surface = 0

b. The mechanical energy at height, h = 150 m, ME₁₅₀ = The potential energy gained = m·g·h

Where;

g = The acceleration due to gravity = 9.81 m/s²

∴ ME₁₅₀ = 750 kg × 9.81 m/s² × 150 m = 1103625 J = 1.103625 MJ

c. The mechanical energy is equivalent to the potential energy of the drone at the 150 m height, therefore, it is conserved

d. The work done by the force = The energy gained

Therefore, where there are <em>n</em> number of forces, the work done by each force = 1.103625/n MJ

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This painting represents the milky way galaxy as it might appear from a distance. Identify the indicated features.
aksik [14]

The indicated features of how the painting represents the milky way galaxy include the following:

  • Spiral arm
  • Bulge
  • Disk

<h3>What is Milky way?</h3>

This is the galaxy which comprises of our solar system and has a milky appearance when it's viewed from the earth.

The painting represented it as a result of the spiral arm and other features which are listed above.

Read more about Milky way here brainly.com/question/13956361

5 0
2 years ago
an athlete runs 5.4 laps around a circular track that is 400.0 m long. If this takes 540 s, what is the average velocity of the
Slav-nsk [51]

Answer:

Average velocity is 0.296 m/s.

Average speed is 4.0  m/s.

Explanation:

Given:

Distance of the circular track is, D=400.0\ m

Number of laps ran is, n=5.4

Time taken for the run is, t=540\ s

Now, total distance covered in 5.4 laps = D_T=D\times n=400\times 5.4=2160\ m

Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.

Distance covered in 0.4 laps is, \textrm{Displacemet}=0.4\times 400=160\ m

Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.

Now, average velocity is given as:

v_{avg}=\frac{\textrm{Displacemet}}{t}=\frac{160}{540}=0.296\ m/s

Average speed is the ratio of total distance covered to total time taken.

So, average speed = \frac{D_T}{t}=\frac{2160}{540}=4\ m/s

6 0
4 years ago
Peter went swimming at a lake with his friends. They arrived early in the morning. Peter walked on the sand around the lake with
lapo4ka [179]
The sun was shining on the sand heating it up causing ot to become hot
4 0
3 years ago
Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *
tigry1 [53]

Answer:

a = 0.45 m/s²

Explanation:

The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".

Given that,

Force, F = 40 N

Mass of the body, m = 88 kg

The net force acting on the body is given by :

F = ma

Where

a is the acceleration of the body

a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2

So, the required acceleration is 0.45 m/s².

4 0
3 years ago
An airplane propeller rotates with an angular speed of 260 rad/s though what angul does the propeller rotate in 5.0s? Give your
ch4aika [34]

Answer:

1300 rad (74522^{\circ})

Explanation:

The angular speed of an object is the rate of change of angular position.

It is given by:

\omega=\frac{\theta}{t}

where

\omega is the angular speed

\theta is the angular displacement of the object

t is the time elapsed

For the propeller rotating in this problem, we have

\omega=260 rad/s is the angular speed

t = 5.0 s is the time elapsed

Therefore, the angular displacement is:

\theta=\omega t=(260)(5.0)=1300 rad

And since 2\pi rad = 360^{\circ}, the angle in degrees is

\theta=\frac{1300}{2\pi}(360)=74522^{\circ}

7 0
4 years ago
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