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tresset_1 [31]
3 years ago
13

Which of these is the best explanation for why 2 negatively charged balloons if put close repel

Physics
1 answer:
Scilla [17]3 years ago
5 0
Opposite charges attract; like charges repel :)
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A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
3 years ago
Im bad at work problems can any one help with this problem ?
lyudmila [28]
We will put the number of trips in the first column, the miles driven in the second column and gallons of fuel used in the third column.

8    7,680    1,010
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4 0
3 years ago
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Dennis_Churaev [7]
A clock and a battery
3 0
3 years ago
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Wheat ground into flour is an example of a ___ change?
EleoNora [17]

Oml... Its physical... Unless if your turning that wheat into bread by using fire it would be chemical.






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6 0
3 years ago
When Woods hits a 0.04593 kg golf ball, the golf ball is usually traveling around 281 kilometers per hour. What average force do
Semenov [28]

Answer:

128.9 N

Explanation:

The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

F=\frac{\Delta p}{\Delta t}

where

F is the force

\Delta p is the change in momentum

\Delta t=0.030 s is the time interval

The change in momentum can be written as

\Delta p = m(v-u)

where

m = 0.04593 kg is the mass of the ball

u = 0 is the initial velocity of the ball

v=281 km/h =78.1 m/s is the final velocity of the ball

Substituting into the original equation, we find the force exerted on the golf ball:

F=\frac{m(v-u)}{\Delta t}=\frac{(0.04593)(78.1-0)}{0.030}=128.9 N

7 0
3 years ago
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