Ask question

Ask question

All categories

3 years ago

15

The largest salami in the world was made in Norway. If a hungry mouse ran around the salami's circumference with a tangential sp

eed of 0.17 m/s, the centripetal acceleration of the mouse was 0.29 m/s^2. What was the radius of the salami?

1 answer:

Nadya [2.5K]3 years ago

8 0

Answer:

Radius of the salami = 9.9 cm

Explanation:

The formula for calculating the radius is given below:

a = v^2/r

where a represents acceleration

v represents velocity

r represents radius

As hungry mouse ran around the salami's circumference with a tangential speed of 0.17 m/s so that means velocity = 0.17 m/s.

The centripetal acceleration of the mouse = 0.29 m/s^2

putting these values in the above formula, we get

0.29 = 0.17^2 / r

After rearranging, we get,

r = 0.17^2 / 0.29

r = 0.099 m

r = 9.9 cm

so the radius of the salami = 9.9 cm

You might be interested in

A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationary seal of m

anzhelika [568]

Answer:

Momentum after collision will be 6000 kgm/sec

Explanation:

We have given mass of the whale = 1000

Initial velocity v = 6 m/sec

It collides with other mass of 200 kg which is at stationary

Initial momentum of the whale = 1000×6 = 6000 kgm/sec

We have to find the momentum after collision

From conservation of momentum

Initial momentum = final momentum

So final momentum = 6000 kgm/sec

5 0

3 years ago

Calculate the linear acceleration (in m/s2) of a car, the 0.310 m radius tires of which have an angular acceleration of 15.0 rad

love history [14]

Answer:

a) The linear acceleration of the car is $4.65\,\frac{m}{s^{2}}$ , b) The tires did 7.46 revolutions in 2.50 seconds from rest.

Explanation:

a) A tire experiments a general plane motion, which is the sum of rotation and translation. The linear acceleration experimented by the car corresponds to the linear acceleration at the center of the tire with respect to the point of contact between tire and ground, whose magnitude is described by the following formula measured in meters per square second:

$\| \vec a \| = \sqrt{a_{r}^{2} + a_{t}^{2}}$

Where:

$a_{r}$ - Magnitude of the radial acceleration, measured in meters per square second.

$a_{t}$ - Magnitude of the tangent acceleration, measured in meters per square second.

Let suppose that tire is moving on a horizontal ground, since radius of curvature is too big, then radial acceleration tends to be zero. So that:

$\| \vec a \| = a_{t}$

$\| \vec a \| = r \cdot \alpha$

Where:

$\alpha$ - Angular acceleration, measured in radians per square second.

$r$ - Radius of rotation (Radius of a tire), measured in meters.

Given that $\alpha = 15\,\frac{rad}{s^{2}}$ and $r = 0.31\,m$ . The linear acceleration experimented by the car is:

$\| \vec a \| = (0.31\,m)\cdot \left(15\,\frac{rad}{s^{2}} \right)$

$\| \vec a \| = 4.65\,\frac{m}{s^{2}}$

The linear acceleration of the car is $4.65\,\frac{m}{s^{2}}$ .

b) Assuming that angular acceleration is constant, the following kinematic equation is used:

$\theta = \theta_{o} + \omega_{o}\cdot t + \frac{1}{2}\cdot \alpha \cdot t^{2}$

Where:

$\theta$ - Final angular position, measured in radians.

$\theta_{o}$ - Initial angular position, measured in radians.

$\omega_{o}$ - Initial angular speed, measured in radians per second.

$\alpha$ - Angular acceleration, measured in radians per square second.

$t$ - Time, measured in seconds.

If $\theta_{o} = 0\,rad$ , $\omega_{o} = 0\,\frac{rad}{s}$ , $\alpha = 15\,\frac{rad}{s^{2}}$ , the final angular position is:

$\theta = 0\,rad + \left(0\,\frac{rad}{s}\right)\cdot (2.50\,s) + \frac{1}{2}\cdot \left(15\,\frac{rad}{s^{2}}\right)\cdot (2.50\,s)^{2}$

$\theta = 46.875\,rad$

Let convert this outcome into revolutions: (1 revolution is equal to 2π radians)

$\theta = 7.46\,rev$

The tires did 7.46 revolutions in 2.50 seconds from rest.

3 0

3 years ago

Explain how we can deduce the temperature of a star by determining its color.

ValentinkaMS [17]

Answer: Stars are bright and have the ability to emit lights of various wavelength. The color of a star plays a significant role. It helps us in determining its temperature. It ranges from reddish color to a bluish-white color. A red color star indicates that the star is of low temperature, whereas a bluish-white star indicates that the star is of high temperature.

7 0

3 years ago

Suppose a ball is thrown vertically upwards from a position P above the ground. It rises to the highest point Q and returns to t

NikAS [45]

Answer:

Net displacement = 0

Distance traveled = 2PQ <_up and down

Explanation:

5 0

3 years ago

Which of the following are ways to improve muscle endurance:

Lyrx [107]

How to gain muscular endurance?<span>Combine strength days with cardio days.Reduce your amount of rest between sets.Do fast-paced, high-intensity lifting.Choose compound movements over isolation.10 Ways to Protect Your Joints >>> Remember: Routine is the enemy.Go for hybrid exercises.<span>Add explosive movements to your workout.</span></span>

4 0

3 years ago