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STALIN [3.7K]
2 years ago
5

A ball is dropped from 256 feet above the ground. It bounces 1/4 as high as it fell.This is true for each successive bounce. Wha

t height will the ball reach on the third bounce?
Mathematics
1 answer:
shtirl [24]2 years ago
6 0
On the third bounce, it will bounce (1/4)*(1/4)*(1/4) = (1/4)^3 times as high.

This means it will bounce up to 256*1/64 = 4 feet high.
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Answer:

s^2 = 0.01

Step-by-step explanation:

Given

Values: 9/5, 9/5, 2, 9/5

Required

Calculate the sample variance

Sample variance is calculated using:

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}

First, we calculate the mean

\overline x = \frac{\sum x}{n}

\overline x = \frac{9/5 + 9/5 + 2 + 9/5}{4}

\overline x = \frac{7.4}{4}

\overline x = 1.85

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1} becomes

s^2 = \frac{(9/5 - 1.85)^2+(9/5 - 1.85)^2+(2 - 1.85)^2+(9/5 - 1.85)^2}{4 - 1}

s^2 = \frac{(-0.05)^2+(-0.05)^2+(0.15)^2+(-0.05)^2}{4 - 1}

s^2 = \frac{0.0025+0.0025+0.0225+0.0025}{3}

s^2 = \frac{0.03}{3}

s^2 = 0.01

<em>Hence, the variance is 0.01</em>

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