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3 years ago

If there were no current in the wire running through the magnet, what could you do to induce an electric current?

1 answer:

5 0

If there is no current running through a good conductor, it's always because
there is no potential difference between its ends, so the electrons in it have
no incentive to go anywhere. If you want a current to flow, just create a potential
difference (a voltage) between the ends of the conductor. You can do that with
a generator, a battery, a solar cell, or some pieces of metal stuck into a moist
potato. As soon as you do that, those electrons wake up, and they all start trying
to fly away from the negative end of the conductor, toward the positive end.

You might be interested in

Find the currents flowing in the circuit in the figure below. (Assume the resistances are

Nitella [24]

By Kirchoff's law in left side loop

$E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3$

similarly kirchoff's law in right side loop

$E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3$

also by junction law we know that

$I_1 = I_2 + I_3$

now by plug in all values we have

$18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3$

$21 = 23.5I_1 + 10.25I_3$

$12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3$

$-15 = 13I_2 - 10.25I_3$

So by solving above equations we have

$I_1 = 0.492 A$

$I_2 = -0.428 A$

$I_3 = 0.920 A$

6 0

4 years ago

The tension in a string from which a 4.0 kg object is suspended in an elevator is equal to 44 N. What is the acceleration of the

Ronch [10]

Answer: 1

Explanation:

Given

Tension is the string $T=44\ N$

mass of object $m=4\ kg$

Tension is greater than the weight of the object i.e. elevator is moving upward

we can write

$\Rightarrow T-mg=ma\\\Rightarrow T=m(g+a)\\\Rightarrow 44=4(10+a)\\\Rightarrow 11=10+a\\\Rightarrow a=1\ m/s^2$

8 0

3 years ago

An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro

Mashutka [201]

1) The distance travelled by the electron is $1\cdot 10^{17} m$

2) The time taken is $4.0\cdot 10^{10}s$

Explanation:

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

$u=5\cdot 10^6 m/s$ is the initial velocity

v = 0 is the final velocity (it comes to a stop)

$a=-1.25\cdot 10^{-4} m/s^2$ is the acceleration

Solving for s, we find the distance travelled:

$s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m$

The total time taken for the electron in its motion can also be found by using another suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

$u=5\cdot 10^6 m/s$

v = 0

$a=-1.25\cdot 10^{-4} m/s^2$

And solving for t, we find the time taken:

$t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0

3 years ago

At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s

mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$ .............1

here I is intensity

so here I1 = 25

because for 0 to 25 there is no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

$\frac{I1}{I2} = (\frac{R2}{R1})^{2}$

$\frac{25}{5} = (\frac{41}{R1})^{2}$

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0

3 years ago

Find the distance (P1, P2) between the points P, and P2:

MA_775_DIABLO [31]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of distance formula.

Distance formula ==>

$\sqrt{( {x2 - x1})^{2} + ( {y2 - y1})^{2} }$

so applying this we get as,

D = underoot (9)^2 + (-5)^2

==> D = 10.29 units

distance = 10.29 units

6 0

3 years ago