The electric potential difference is 7.5 V.
Electric potential difference between two points is defined as the work done in moving unit positive charge between the two points. Electric potential difference can also be defined as the work done W per unit charge q in an electric field.
......(1)
Work done by a force is the product of the force F and the displacement s made in the direction of the force. Assuming that the displacement is parallel to the line of action of the force,
......(2)
Rewrite equation (1) using equation (2).
......(3)
Substitute the given values of force, displacement and charge in the equation (3).
The potential difference between the two points is 7.5 V
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Question
</h2>
A particle, mass 0.25 kg is at a position (<em>-7i + 7j + 5k</em>) m, has a velocity (<em>6i - j + 4k</em>) m/s, and is subject to a force (<em>-5i + 0j - k</em>) N. What is the magnitude of the torque on the particle about the origin?
<h2>
Answer:</h2>
47.94Nm
<h2>
Explanation:</h2>
The torque (τ) on a particle subject to a force (represented as force vector F) at a position (represented as position vector r) about the origin is given by the cross product of the position vector r for the point of application of a force and the force F. i.e
τ = r x F
Given:
r = (-7i + 7j + 5k) m
F = (-5i + 0j - k) N
| i j k |
r x F = | -7 7 5 |
| -5 0 -1 |
r x F = i(-7 - 0) - j(7+25) + k(0+35)
r x F = i(-7) - j(32) + k(35)
r x F = -7i - 32j + 35k
Therefore the torque τ = -7i - 32j + 35k
The magnitude of the torque is therefore;
|τ| =
|τ| =
|τ| =
|τ| = 47.94Nm
The magnitude of the torque on the particle about the origin is 47.94Nm
Answer:
In my opinion is Sally
Explanation:
It depend on your opinion,✨
Answer: Photoelectric wave
Explanation: Because it represents an interaction between light and matter that describes light as an electromagnetic wave.
<span>PV = nRT
moles of H2 = 1/2 = 0.5
moles of He = 1/4 =0.25
T = 273 + 27
partial pressure of H2
Px1 = 0.5x0.083x300
P=12.45 atmospheres
PP of He
px1 = 0.25x0.083x300
P =6 22 atmospheres
Totla pressure = 6.22 + 12.45 = 18.68 atm</span>