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3 years ago

7

What is the average kinetic energy in joules of hydrogen atoms on the 5500ºc surface of the sun?

1 answer:

Masteriza [31]3 years ago

7 0

The kinetic energy is related to the temperature of the system using this formula:

E = (3/2)kT
where
k is the Boltzmann's constant (1.38×10⁻²³ J/K)

The temperature in K is:
T = 5500 +273 = 5773 K

E = (3/2)(1.38×10⁻²³ J/K)(5773 K)
<em>E = 1.195×10⁻¹⁹ J</em>

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LenaWriter [7]

Answer:

The person with locked legs will experience greater impact force.

Explanation:

Let the two persons be of nearly equal mass (say m)

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nikitadnepr [17]

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2 years ago

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alukav5142 [94]

Explanation:

(a) It is known that equation for transverse wave is given as follows.

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Now, we will compare above equation with the standard form of transeverse wave equation,

y = $A sin(kx + \omega t)$

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x is displacement = 1.40 m

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v(t) = -0.84 m/s

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a(t) = $\frac{dv}{dt}$

a(t) = $-A \omega 2sin(kx + \omega t)$

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T = $\frac{2 \pi}{\omega}$

T = $\frac{2 \pi}{4 \pi}$

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Now, we will calculate the speed of propagation of wave as follows.

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