Question

What is the average kinetic energy in joules of hydrogen atoms on the 5500ºc surface of the sun?

Answer 1

The kinetic energy is related to the temperature of the system using this formula:

E = (3/2)kT
where
k is the Boltzmann's constant (1.38×10⁻²³ J/K)

The temperature in K is:
T = 5500 +273 = 5773 K

E = (3/2)(1.38×10⁻²³ J/K)(5773 K)
E = 1.195×10⁻¹⁹ J