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Answer:


Explanation:
<u>Temperature Units Conversion
</u>
The conversion formula between Celsius and Fahrenheit temperature scales is well-known. But we'll use the provided data to derive the formula. Let's model the relationship between Fahrenheit (F) and Celsius (C) as a linear function like

Where m and b must be computed according to the pair of conditions given. The values for each temperature scale are (C,F)=(0,32) and (100,212). Replacing the first value

It means that

By using the second point

Solving for m

Simplifying

So, the conversion formula is

Which is the widely known formula for temperature conversion
Solving for C, we get the inverse relation

Answer:
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