What is the correct answer?

Acetic acid, CH3CO2H, reacts with ethanol, C2H5OH, to form water and ethyl acetate, CH3CO2C2H5. The equilibrium constant for thi

Irina-Kira [14]

Explanation:

The initial concentrations for a mixture :

Acetic acid at equilibrium = 0.15 M

Ethanol at equilibrium = 0.15 M

Ethyl acetate at equilibrium = 0.40 M

Water at equilibrium = 0.40 M

$CH3COOH + C_2H_5OH\rightleftharpoons CH_3CO_2C_2H_5+H_2O$

Initially:

0.15 M 0.15 M 0.40 M 0.40 M

At equilibrium

(0.15-x)M (0.15-x) M (0.40+x) M (0.40+x) M

The equilibrium constant is given by expression

$K_c=\frac{[CH_3CO_2C_2H_5][H_2O]}{[CH_3COOH][C_2H_5OH]}$

$4.0=\frac{(0.40-x)\times (0.40-x)}{(0.15+x)\times (0.15+x)}$

Solving for x:

x = 0.0333

The equilibrium concentrations for a mixture :

Acetic acid at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M

Ethanol at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M

Ethyl acetate at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M

Water at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M

4 0

3 years ago

calculate the atomic number of an element whose neutral atom has four electrons in its valence shell and its valence shell is th

insens350 [35]

Answer:

The atomic number of the atom is 14.

Explanation:

The following data were obtained from the question:

Valence electrons = 4

Atomic number =.?

From the question given, we were told that the valence electron is in the m shell. Thus, we can say:

M shell = 4 electrons

The number of shells of the atom can be written in the order K, L, M with M as the last shell because we were told that the valence electrons i.e electrons in the outer shell is located at the M shell.

From a detailed knowledge of atom,

K shell = 1st shell

L shell = 2nd shell

M shell = 3rd shell

The first shell, K of an atom can only accommodate 2 electrons while others can accommodate a maximum of 8 electrons.

Note: we can only put electrons in another shell if a shell is already having 8 electrons. This rule only applies to the 2nd shell and above.

Thus, the atom in question has the following electrons:

K shell = 1st shell = 2 electrons

L shell = 2nd shell = 8 electrons

M shell = 3rd shell = 4 electrons

To get the atomic number of the atoms, we simply add all the electrons together.

This is illustrated below:

Atomic number = 2 + 8 + 4

Atomic number = 14

Therefore, the atomic number of the atom is 14.

6 0

2 years ago

If 1.80 moles of NaCl was dissolved in enough water to make 3.60 L of solution, what is the Molarity?

sweet-ann [11.9K]

Answer:

0.5M

Explanation:

The equation for molarity is:

M = $\frac{mol}{liters}$ ; where the "M" stands for molarity, the "mol" stands for moles of solute and the "liters" means the volume in liters of solution.

We are given that there are:

1.80 moles of NaCl (the moles of solute)

3.60 Liters of solution (the volume in liters of solution)

Now we just plug those numbers into the formula and get our answer:

M= $\frac{1.80mol}{3.60L}$ = 0.5M

After doing the math and dividing the moles of solute by the liters of solution, we get that the molarity of the solution is 0.5M.

8 0

3 years ago

On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+

Ostrovityanka [42]

Answer:

Acid(BSA) = CH₃COOH

Base (BSB) = H₂O

Conjugate base (CB) = CH₃COO⁻

Conjugate acid (CA) = H₃O⁺

Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

7 0

2 years ago

An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify

klasskru [66]

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

8 0

2 years ago