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3 years ago

How many molecules are in 23 Moles of oxygen o2

Chemistry

1 answer:

loris [4]3 years ago

6 0

Answer:

1.38×10^25 molecules

Explanation:

Applying n= (no. of molcules)/NA

23 = N/6.02×10^23

= 1.38×10^25 molecules

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Find the number of moles of water that can be formed if you have 170 mol of hydrogen gas and 80 mol of oxygen gas. Express your

Sav [38]

Answer: The amount of water that can be formed is 160 moles

Explanation:

We are given:

Moles of hydrogen gas = 170 moles

Moles of oxygen gas = 80 moles

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

$2H_2+O_2\rightarrow 2H_2O$

By Stoichiometry of the reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas

So, 80 moles of oxygen gas will react with = $\frac{2}{1}\times 80=160mol$ of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of oxygen gas produces 2 moles of water

So, 80 moles of oxygen gas will produce = $\frac{2}{1}\times 80=160moles$ of water

Hence, the amount of water that can be formed is 160 moles

3 0

3 years ago

6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation

uranmaximum [27]

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

6 0

2 years ago

Alkaline batteries are non-rechargeable. Why do alkaline batteries eventually stop working?

scoray [572]

Answer:

Alkaline batteries stop working when all of the manganese dioxide has been converted.

Explanation: Hope it helps you :)))

Have a good day

4 0

2 years ago

8 moles Cl to grams 3

kirill [66]

Answer: I don’t understand what your asking elaborate more

Explanation:

7 0

3 years ago

Consider a wildflower population with the following allele and genotype frequencies. Frequency of the CR allele: p = 0.6 Frequen

k0ka [10]

NO, It Isn't

Ideally a population in Hardy Weinberg equilibrium should hold true to the following equation for genotypic frequencies of an allele;

P² + 2pq + q² = 1

Explanation:

We are provided with allelic frequencies hence we can derive the genotypic frequencies; (CR allele: p = 0.6 Frequency of the CW allele: q = 0.4)

P² = 0.6 ^2 = 0.36

2pq = 2 * 0.6 * 0.4 = 0.48

q² = 0.4 ^ 2 = 0.16

Lets find out if all add up to as supposed to;

0.36 + 0.48 + 0.16 = 1

Converting to percentages is easy – just multiply by 100

36 % CRCR
48% CRCW
and 16 % CWCW

The population provided is not in equilibrium because their percentages vary widely to that the expected Hardy Weinberg's equilibrium percentages. This could be attributed to factors like;

Migration
Mutations,
There is natural selection in progress in the population
There is gene flow

Learn More:

For more on Hardy Weinberg's equilibrium check out;

brainly.com/question/9916141

#LearnWithBrainly

5 0

3 years ago