Solution :
Given :
Initial temperature of the refrigerant is :
= ( 39.37 + 273 ) K
= 312.3 K
Room which is maintained at constant temperature is :
= (22+273) K
= 295 K
The thermal energy transferred to the room is :
Q = 400 kJ
=
Therefore, the total entropy generation during the thermal energy process is :
Here, -Q = heat is leaving the system maintained at a temperature of K.
+Q = heat is entering the system maintained at a temperature of K.
Therefore, substituting the values :
= [-1280.8197 + 1355.9322]
= 75.1125 J/K
= 0.0751125 kJ/K
= 0.075 kJ/K
There are 20 milligrams in 0.2 decigrams
The atomic number represents the amount of protons in an atom.
Answer:
Explanation:
Hello,
For the given chemical reaction:
Whose heat of reaction is 464.8 kJ/mol which means that energy is absorbed due to the chemical reaction, we can compute the moles of calcium carbide via the following relationship:
Then, since the molar mass of calcium carbide is 64 g/mol, the yielded mass turns out:
Best regards.
Explanation:
In first one it should be 2Mg
and in second = 2Mgo
hope it helps....