All categories

3 years ago

Write the equations in graphing form, then state the vertex of the parabola or the center and radius of the circle.

Mathematics

1 answer:

UNO [17]3 years ago

4 0

$y=2x^2+16\\y=2(x)^2+16$

It is a positive-slope parabola with vertex of (0,16) "concave up"

You might be interested in

I forgot to do slopes

Minchanka [31]

To find the slope of the line, use the rise over run formula:

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Take any two points from the line and plug them into the formula.

(0,0) and (10, 5)

$\frac{5 - 0}{10 - 0} = \frac{5}{10} = 0.5$

The slope of the line is 0.5.

Using the form y = mx, the following equation will be your answer:

$y = 0.5x$

7 0

3 years ago

PLEASE HELP! I AM BEING TIMED!! will give you brainliest!!!

Gre4nikov [31]

Yea this is a Hamilton circuit. This is because it goes through A, C, E, B, D and return back to A without overlapping and successfully reaching each point.

5 0

3 years ago

One gallon of water weighs 8.34 pounds. How much does 6 gallons of water weigh? Show your work, including labeling your answer w

maxonik [38]

Answer:

50.04 pounds

Step-by-step explanation:

If 1 gallon weighs 8.34 pounds,

all you have to do is multiply 8.34 by 6

to get what 6 gallons would weigh.

8 0

3 years ago

Which of the following sequences are convergent? Select all that apply

alexandr402 [8]

R=1/5 and r=2/3 are the answers

3 0

3 years ago

Read 2 more answers

2x+8y=3 and 4x-3y=2 value of x and y.. plzz help me

lesya692 [45]

Answer:

Set a system of equations:

$\left \{ {{2x+8y=3} \atop {4x-3y=2}} \right.$

Multiply the whole upper equation by 2 and the whole bottom equation by 1 so their x-value equals:

$\left \{ {{2(2)x+8(2)y=3(2)} \atop {4(1)x-3(1)y=2(1)}} \right.\\\\=\left \{ {{4x+16y=6} \atop {4x-3y=2}} \right.$

Subtract the upper equation by the bottom equation & solve for y:

$(4x-4x)+(16y-(-3y))=6-2\\\\19y=4\\\\y=\frac{4}{19}$

Substitute in the y-value to a equation to find x:

$2x+8y=3\\\\2x+8(\frac{4}{19} )=3\\\\2x=3-\frac{32}{19} =\frac{57}{19} -\frac{32}{19} =\frac{25}{19} \\\\x=\frac{\frac{25}{19}}{2} =\frac{25}{19}*\frac{1}{2} =\frac{25}{38}$

Therefore, the answer would be:

$\left \{ {{y=\frac{4}{19} } \atop {x=\frac{25}{38} }} \right.$

6 0

3 years ago