1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lina20 [59]
4 years ago
11

ocho libros cada uno de 4.0cm de espesor y masa de 1.8 kg, se encuentra en posición horizontal sobre una mesa ¿ cuanto trabajo s

e requiere para apilarlos uno sobre otro?
Physics
1 answer:
elena-14-01-66 [18.8K]4 years ago
5 0

Answer:

El trabajo requerido es 1.978 julios

Explanation:

La cantidad de trabajo para apilar cada libro = Masa del libro, m × Aceleración debido a la gravedad, g × Altura del libro, h

La altura de cada libro = 4.0 cm. = 0.004 m

El primer libro es la primera capa, otros libros se colocan encima

Altura del primer libro levantado = 0

El trabajo realizado en el primer libro = 1.8 × 9.81 × 0 = 0

Trabajo realizado para el segundo libro = 1.8 * 9.81 * 0.004 = 0.071 J

Trabajo realizado para el tercer libro = 1.8 * 9.81 * 0.004 * 2 = 0.141 J

Trabajo realizado para el cuarto libro = 1.8 * 9.81 * 0.004 * 3 = 0.212 J

Trabajo realizado para el quinto libro = 1.8 * 9.81 * 0.004 * 4 = 0.283 J

Trabajo realizado para el sexto libro = 1.8 * 9.81 * 0.004 * 5 = 0.353 J

Trabajo realizado para el séptimo libro = 1.8 * 9.81 * 0.004 * 6 = 0.424 J

Trabajo realizado para el octavo libro = 1.8 * 9.81 * 0.004 * 7 = 0.494 J

El trabajo total realizado = 0.071 + 0.141 + 0.212 + 0.283 +0.353 + 0.424 + 0.494 = 1.978 J.

You might be interested in
Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise t
romanna [79]

Answer:

Both charges must have the same charge, Qt/2.

Explanation:

Let the two charges have charge Q1 and Q2, respectively.

Use Coulombs's Law to find an expression for the force between the two charges.

F = k_e\frac{Q_1Q_2}{r^2}, where

Ke is Coulomb's contant and

r is the distance between the charges.

We know from the question that

Q1 + Q2 = Qt

So,

Q2 = Qt - Q1

F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}

Simplify to obtain,

F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)

In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.

Differentiate F with respect to Q1,

\frac{dF}{dQ_1}  = \frac{k_e}{r^2} (Q_t - 2Q_1)

Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.

\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}

It follows that

Q_2 = \frac{Q_t}{2}.

6 0
3 years ago
A 24-cm circumference loop of wire has a resistance of 0.14 Ω. The loop is placed between the poles of an electromagnet, and a f
Triss [41]

Answer:

The induced current in the loop is 1.2 A

Explanation:

Given;

length of the wire, L = 24 cm = 0.24 m

resistance of the wire, R = 0.14 Ω.

magnetic field strength, B = 0.55 T

time, t = 15 ms = 15 x 10⁻³ s

Circumference of a circle is given as;

L = 2πr

0.24 = 2πr

r = 0.24 / 2π

r = 0.0382 m

Area of a loop is given as;

A = πr²

A = π (0.0382)²

A = 0.004585 m²

Induced emf is given as;

emf = -\frac{\delta \phi}{dt}

Ф = ΔB x A

Ф = ( 0 - 0.55 T) x 0.004585 m²

Ф = -0.002522 T.m²

emf = - (\frac{-0.002522}{15*10^{-3}} )\\\\emf = 0.168 \ V

According to ohm's law;

V = IR

Where;

I is current

The induced current in the loop is calculated as;

I = V / R

I = 0.168 / 0.14

I = 1.2 A

Therefore, the induced current in the loop is 1.2 A

4 0
3 years ago
At some instant and location the electric field associated with an electromagnetic wave in vacuum has the strength 96.5 V/m. Fin
prisoha [69]

Answer:

B = 32.17 x 10^-8 Tesla

u = 8.24 x 10^-8 J/m^3

P/A = 24.72 W/m^2

Explanation:

E = 96.5 V/m

velocity of light, c = 3 x 10^8 m/s

Let B be the magnetic field.

The relation between the electric field strength and the magnetic field strength is given by

B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla

Let u be the energy density.

u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}

u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}

u = 8.24 x 10^-8 J/m^3

Let Power flow per unit area is

P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2

7 0
3 years ago
La taille d'un molécule d'eau est 0,4nm
pogonyaev
2mm.
0,4x 5x10^6 = 2x10^6
1nm = 1x10^-6mm
2x10^6nm = 2mm.
8 0
3 years ago
hallar un numero de dos cifras sabiendo que la suma de las cifras es 12 y que la primera de ellas es el triple de la segunda
Natali [406]

Answer:

93 o 39.

Explanation:

Hola.

En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:

1. Definimos <em>x</em> como el primer dígito y <em>y</em> como el segundo, por lo tanto, como su suma es 12, escribimos:

<em>x</em> + <em>y</em> = 12

2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:

<em>x</em> = 3 <em>y</em>

De este modo, podemos resolver para <em>y</em>:

3 <em>y</em> + <em>y</em> = 12

4 <em>y</em> = 12

<em>y</em> = 12 / 4

<em>y</em> = 3

Y para <em>x</em>:

<em>x</em> = 3 <em>y</em>

<em>x</em> = 3 * 3

<em>x</em> = 9

Así, el número puede ser 93 o 39.

¡Saludos!

3 0
3 years ago
Other questions:
  • Please help!
    10·2 answers
  • Describe the arrangement of the sun moon and earth during a solar eclipse and a lunar eclipse
    14·1 answer
  • The drag coefficient of a car at the design conditions of 1 atm, 25°c, and 90 km/h is to be determined experimentally in a large
    15·1 answer
  • What is the term to describe the rate of flow of electricity?
    11·1 answer
  • A book rests on a table. The earth pulls down on the book through the weight force. Which force is the reaction force to the wei
    14·1 answer
  • "A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at
    6·1 answer
  • A hollow conductor is positively charged. Asmall uncharged metal ball is lowered by a silk thread through asmall opening in the
    15·1 answer
  • The moon's mass is ____?
    5·2 answers
  • 1.
    6·1 answer
  • I have a question
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!