All categories

3 years ago

hallar un numero de dos cifras sabiendo que la suma de las cifras es 12 y que la primera de ellas es el triple de la segunda

Physics

1 answer:

Natali [406]3 years ago

3 0

Answer:

93 o 39.

Explanation:

Hola.

En este caso, podemos resolver este problema por medio del planteamiento de las siguientes ecuaciones:

1. Definimos x como el primer dígito y y como el segundo, por lo tanto, como su suma es 12, escribimos:

x + y = 12

2. Ahora, dado que el primer dígito, x es el triple del segundo, escribimos:

x = 3 y

De este modo, podemos resolver para y:

3 y + y = 12

4 y = 12

y = 12 / 4

y = 3

Y para x:

x = 3 y

x = 3 * 3

x = 9

Así, el número puede ser 93 o 39.

¡Saludos!

You might be interested in

A pool can be filled by a pipe in 3 hours. it takes 3 times as long for another pipe to empty the pool. how long will it take to

Mila [183]

There is need 4.5 hours to fill the pool in case if both pipes are open

7 0

3 years ago

Car A is parked on a hill and Car B is driving down a level highway. Which statement best describes the two cars? A) Car A has k

12345 [234]

The answer is b because kinetic energy is the energy of motion, while potential energy is the energy stored in an object because of its position.

5 0

4 years ago

Read 2 more answers

Fifty grams of water cooled from 50 'C to 10 'C. If the specific heat of water is 4.2 , how much heat was released ?

ryzh [129]

THe anwser woul have to be C

4 0

3 years ago

Is the amount of friction greater between rough surfaces or smooth surfaces? Why?

nalin [4]

Answer:

friction occurs because no surface is perfectly smooth.

Explanation:

rougher surfaces have more friction between them.

6 0

3 years ago

An electric car accelerates for 8.0 s by drawing energy from its 320-V battery pack. During this time, 1300 C worth of electrons

kati45 [8]

(a) $8.13\cdot 10^{-21}$

The magnitude of the charge of one electron is

$q=1.6\cdot 10^{-19}C$

Here the total amount of charge that passed through the battery pack is

Q = 1300 C

So this total charge is given by

Q = Nq

where

N is the number of electrons that has moved through the battery

Solving for N,

$N=\frac{Q}{q}=\frac{1300 C}{1.6\cdot 10^{-19} C}=8.13\cdot 10^{-21}$

(b) $4.16\cdot 10^5 J$

First, we can find the current through the battery, which is given by the ratio between the total charge (Q = 1300 C) and the time interval (t = 8.0 s):

$I=\frac{Q}{t}=\frac{1300 C}{8.0 s}=162.5 A$

Now we can find the power, which is given by:

$P=VI$

where

V = 320 V is the voltage

I = 162.5 A is the current

Subsituting,

$P=(320 V)(162.5 A)=52,000 W$

And now we can find the total energy transferred, which is the product between the power and the time:

$E=Pt = (52,000 W)(8.0 s)=4.16\cdot 10^5 J$

(c) 69.7 hp

Now we have to convert the power from Watt to horsepower.

We know that

1 hp = 746 W

So we can set up the following proportion:

1 hp : 746 W = x : 52,000 W

And by solving for x, we find the power in horsepower:

$x=\frac{1 hp \cdot 52,000 W}{746 W}=69.7 hp$

5 0

4 years ago