Answer:
B. Cell Type
Explanation:
that is the answer i believe
Sandy would reach an incorrect outcome.that's because she will repeat this mistake in the future too.
Answer:
it is iodine it seems very right
Answer:
0.006 mol of CaCl2 are present
Explanation:
Use dimensional analysis for this:
60.0 mL CaCl2/1 * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol
If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.
**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.
Hope this helps :)
Use Ideal Gas equation since values are given in Pressure (P), Volume (V), Temperature (T).
P V = n R T ; n= PV / RT
You can't use 1 mole= 22.4 L equation. Temperature and pressure values are not standard. ( 1 atm, 0
To choose the value of R ( gas constant), check out the units of other values in the equation. They are in atm,liter, kelvin, and mole. So, its value is 0.082 L atm/ K mol.
P= 0.97 atm
V= 35.83 * 10 ⁻³ L (conversion from ml to, just multiplied by 10 ⁻³ )
R= 0.082 L atm/ K mol
T= (25.3 + 273) K ( recall Kelvin = Celcius + 273; K= °C + 273<span>)
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Substitute values into equation of n= PV / RT
n= (0.97 atm) (35.83 * 10 ⁻³ L) / (0.082 L atm/ K mol) (298.3 K)= 0.014 mole
The answer is 0.014 mole
