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Dima020 [189]
2 years ago
7

Find a polynomial function of degree 7 with a leading coefficient of 1 and with - 3 as a zero of multiplicity 3,0 as a zero of m

ultiplicity 3, and 3 as a zero of multiplicity 1.
Mathematics
1 answer:
jeyben [28]2 years ago
5 0

The <em>least</em> polynomial in <em>standard</em> form is defined by the function f(x) = x⁷ + 6 · x⁶ - 54 · x⁴ - 81 · x³.

<h3>How to determine the least polynomial given a set of roots and a leading coefficient</h3>

Polynomials can be expressed as a product of binomials of the form (x - r) multiplied by a <em>leading</em> coefficient. The <em>least</em> polynomial contain the number of roots presented in statement, whose <em>factor</em> form is shown below:

f(x) = 1 · (x + 3)³ · x³ · (x - 3)

f(x) = (x + 3)³ · (x⁴ - 3 · x³)

f(x) = (x³ + 9 · x² + 27 · x + 27) · (x⁴ - 3 · x³)

f(x) = x⁷ + 9 · x⁶  + 27 · x⁵ + 27 · x⁴ - 3 · x⁶ - 27 · x⁵ - 81 · x⁴ - 81 · x³

f(x) = x⁷ + 6 · x⁶ - 54 · x⁴ - 81 · x³

The <em>least</em> polynomial in <em>standard</em> form is defined by the function f(x) = x⁷ + 6 · x⁶ - 54 · x⁴ - 81 · x³.

To learn more on polynomials: brainly.com/question/11536910

#SPJ1

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3 years ago
What is the radius and diameter of the following circle?
belka [17]

Answer:

Radius = 5.1

Diameter = 10.2

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Radius is a straight line that connects the center of a circle to a point on the circumference (outside of the circle).

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4 years ago
They have a rectangle ABCD as shown below, where AB = 24cm BC = 10cm and AE = 13cm
alex41 [277]

Answer:

A. Area of ABCD = 240 cm^{2}

B. 60 cm

C. 36 cm

D. 50 cm

Step-by-step explanation:

Given: AB = 24cm BC = 10cm and AE = 13cm.

A.  Since a rectangle is a 2 dimensional figure, it has no volume but area.

So that,

the area of the rectangle ABCD = length x width

                                                     = 24 x 10

                                                     = 240 cm^{2}

B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.

BD^{2} = BC^{2} + DC^{2}

       = 10^{2} + 24^{2}

       = 676

BD = \sqrt{676}

     = 26

BD = 26 cm

so that,

the circumference of BCD = 10 + 24 + 26

                                         =   60 cm

C. To calculate the circumference of the BEC triangle,

AC = 26 cm, AE = 13 cm

CE = 26 - 13

     = 13 cm

CE = 13 cm

The circumference of the BEC triangle = 13 + 13 + 10

                                                                 = 36 cm

D. The circumference of the DEC triangle = 13 + 13 + 24

                                                                 = 50 cm

       

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