All categories

3 years ago

A wave has a wavelength of 2.30 m and a frequency of 370.0 Hz. What is the speed of the wave?

Physics

2 answers:

andreyandreev [35.5K]3 years ago

4 0

Answer is 851 on edge :)

Alborosie3 years ago

4 0

Answer : The speed of the wave is 851 m/s

Explanation :

It is given that,

Wavelength of a wave is, λ = 2.3 m

The frequency of the wave is, υ = 370 Hz

The speed of the wave is given as :

$speed=\dfrac{distance}{time}$

In case of wave, the distance is equal to the wavelength of the wave and the time taken is equal to the inverse of frequency i.e. $T=\dfrac{1}{\nu}$ .

So, $v=\dfrac{\lambda}{T}$

or $v=\nu \times \lambda$

$v=370\ Hz\times 2.3\ m$

v = 851 m/s

So, the speed of the wave is 851 m/s

You might be interested in

What role did gravity play in the formation of the planets?

joja [24]

Your answer would be D.
If an object has mass, it has gravity, and the more mass it has, the stronger its gravity. During the formation of planets, essentially, various matter and elements pulled and fused together (because of the gravity), forming planetesimals.

3 0

3 years ago

Read 2 more answers

Explain how a form of energy is used in daily life

hram777 [196]

Answer:

When we talk about residential uses of energy, these are the most basic uses of energy . They include watching television, washing clothes, heating and lighting at home , taking a shower, working from home on your laptop or computer, running appliances and cooking.

3 0

3 years ago

Vector a cross b whole square

skad [1K]

Answer:

Kriss go Brrrrrrrrrrr

Explanation:

4 0

3 years ago

You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1

drek231 [11]

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

The given parameters;

Mass of the pendulum, = M
Length of the pendulum, = L
Initial angular speed, $\omega _i$ = 1 rad/s

The moment of inertia of the rod about the end is given as;

$I_i = \frac{1}{3} ML^2$

The moment of inertia of the rod between the middle and the end is calculated as;

$I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}$

Apply the principle of conservation of angular momentum as shown below;

$I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f$

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

Learn more about moment of inertia of uniform rod here: brainly.com/question/15648129

3 0

3 years ago

1. what planet/star is the center of the solar system

puteri [66]

I need more details like r u reading from something

8 0

4 years ago