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2 years ago

3) Principles of rectilinear proportion of light 9

Physics

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:Principle of rectilinear propagation of light

Explanation:Principle of rectilinear propagation of light

Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.

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Choose the correct statement concerning units of power or energy. a. A kilojoule (kJ) is a unit of power. b. A gigawatt (GW) is

sergiy2304 [10]

Answer:

A kilowatt (kW) is a unit of power.

Explanation:

The power of an object is given by :

$P=\dfrac{E}{t}$

Here,

E is the energy required

t is time

The SI unit of power is Watts and the SI unit of energy is Joule. the commercial unit of energy is kilowatt per hour.

Option (1) : A kilojoule (kJ) is a unit of power is incorrect.

Option (2) : A gigawatt (GW) is a unit of energy is incorrect.

Option (3) : A watt (W) is a unit of energy is incorrect.

Option (4) : A kilowatt x hour per year (kWh/yr) is a unit of energy is incorrect.

Option (4) : A kilowatt (kW) is a unit of power is correct.

Hence, the correct option is (d).

3 0

3 years ago

When do vernal equinoxes usually occur? autumnal?

shepuryov [24]

Spring tides occur twice each lunar month all year long without regard to the season. Neap tides, which also occur twice a month, happen when the sun and moon are at right angles to each other. ... The moon appears full when the Earth is between the moon and the sun

7 0

3 years ago

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m

serious [3.7K]

Answer:920.31 J

Explanation:

Given

Volume of water (V) $=14.1 cm^3$

mass(m) $=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm$

Temperature $=8.4^{\circ} C$

Final Temperature $=-7.2 ^{\circ}C$

specific heat of water(c) $=4.184 J/g-^{\circ}C$

Therefore heat required to removed is

$Q=mc(\Delta T)$

$Q=14.1\times 4.184\times (8.4-(-7.2))$

$Q=920.31 J$

3 0

4 years ago

a 5.0 kg block is at rest on a horizontal floor. if you push horizontally on the 5.0 kg block with a force of 15.0 n, it just st

zheka24 [161]

For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.

Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.

Using the formula: F = μmg

Where,

F = Force , m= mass of the block and g = gravity.

and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²

We can get: μ = F/(mg)

μ = 15/49

μ =0.306

Therefore, coefficient of static friction (μ) = 0.306.

To learn more about static friction visit the link- brainly.com/question/13680415

#SPJ4

4 0

2 years ago

A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used

Bad White [126]

Answer:

$N=1.64\times10^{19}$

$R=19.54\Omega$

$V=10.28V$

Explanation:

By definition $I=Q/t$ , so we can calculate the total charge that went through the filament since we know the electric current and the time. If the charge of one electron is e, then the total charge will be given by Q=Ne. Combining these equations we get the number of electrons as:

$N=\frac{Q}{e}=\frac{It}{e}=\frac{(0.526A)(5s)}{1.602\times10^{-19}C}=1.64\times10^{19}$

Since the resistivity of tungsten (W) is $\rho_W=5.6
\times10^{-8}\Omega m$ , then resistance can be calculated using the formula:

$R=\rho_W\frac{L}{A}=\rho_W\frac{L}{\pi r^2}=(5.6\times10^{-8}\Omega m)\frac{(0.58m)}{\pi (0.000023m)^2}=19.54\Omega$

Where we already obtained the radius from the diameter. Finally the Voltage will be given by the formula:

$V=RI=(19.54\Omega)(0.526A)=10.28V$

3 0

3 years ago

3) Principles of rectilinear proportion of light 9​

3) Principles of rectilinear proportion of light 9