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2 years ago

3) Principles of rectilinear proportion of light 9

Physics

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:Principle of rectilinear propagation of light

Explanation:Principle of rectilinear propagation of light

Rectilinear propagation of light refers to the propensity of light to travel along a straight line without any interference in its trajectory. ... It is because light travels along a straight line and leaves only the areas where the object interferes.

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The force F⃗ pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for

abruzzese [7]

Answer:

The answer is " $\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}$ "

Explanation:

$\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}$

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3 years ago

What is the angle of reflection?

hoa [83]

I can guarantee you that it is not
C.<span>the angle that the incident ray makes with a line drawn perpendicular to the reflecting surface I hope this somewhat helps</span>

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3 years ago

Two children of about the same weight are playing at the playground. They both climb up to the top of a small tower. One slides

olya-2409 [2.1K]

Answer:

Explanation:

D) The overall work done by gravity is zero

This statement is correct .

If m be the mass of each of the children and h be the height of tower

work done by gravity on the boys in going up = - mgh

it is so because force applied by gravity = mg downwards and displacement

is upwards

work done will be negative = - mgh

Work done by gravity on boys when they come down = + mgh because both force and displacement are downwards .

Hence total work done = - mgh + mgh = 0.

The children will have same kinetic energy as the inclined surface is friction-less so no energy will be dissipated hence addition of energy to boys in both the cases will be same.

4 0

3 years ago

You are designing a delivery ramp for crates containing exercise equipment. The 1890 N crates will move at 1.8 m/s at the top of

Mashcka [7]

Answer:

K = 588.3 N/m

Explanation:

From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):

Fe - Ff - W*sin(22) = 0 Replacing Fe = K*X and then solving for X:

$X = \frac{Ff + W*sin(22)}{K}=\frac{1223}{K}$

By conservation of energy:

$\frac{K*X^{2}}{2}-mg*d*sin(22)-\frac{m*V^{2}}{2}=-Ff*d$

Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:

K = 588.3 N/m

6 0

3 years ago

Two long, parallel wires carry currents of different magnitudes. if the amount of current in each wire is doubled, what happens

Mrac [35]

The force per unit of length between two wires carrying current is
$\frac{F}{L}= \frac{\mu_0 I_1 I_2}{2 \pi r}$
where I1 and I2 are the currents in the two wires, while r is the distance between them.

We can see from the formula that the force is proportional to the product between I1 and I2: $F \sim I_1 I_2$
so, if we double both I1 and I2, we get a factor 4:
$F' \sim (2I_1 )(2I_2)=4 I_1 I_2 =4 F$
so, the force between the wires will be 4 times the original value.

4 0

3 years ago

3) Principles of rectilinear proportion of light 9​

3) Principles of rectilinear proportion of light 9