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3 years ago

Can someone help me with these questions please. I will mark brainliest

Physics

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

3: I can´t see the text/image, but it depend on the mass and the force applied to the ball, if both are too high, it will be harder to make a home run. (Second law)

4:It would be easier to make a home run because there is no interruption between the ball and the space the same travels. (Third law)

Explanation:

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the Space Program has benefitted people in everyday life. Describe two ways in which people can benefit

ycow [4]

So we can know what is in space maybe weird or interesting stuff

8 0

3 years ago

Need help in Psychology. Please help! Which of the following statements best describes abductive reasoning? A.I think,therefore

Pepsi [2]

The "D) People perceive objects as a whole" statement best describes an abductive reasoning. The abductive reasoning often has incomplete information as the base of its reasoning and the conclusion for this type of reasoning is not absolute. There will always be additional pieces of evidence and factors that could change the conclusion of this reasoning. Therefore<span> D statement is the most suitable answer.</span>

5 0

3 years ago

1. What is the potential energy of a 5.0-kg

babymother [125]

Answer:

C. 98 J

Explanation:

The appropriate formula is ...

PE = mgh . . . . . m is mass; below, m is meters

PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2

PE = 98 J

5 0

3 years ago

A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/

Elena-2011 [213]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

$KE_i + PE_i = KE_f + PE_f$

$\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0$

$\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2$

So by solving above equation we will have

$v_f = 84.3 m/s$

now in order to find the momentum we can use

$P = mv$

$P = 1.25 \times 84.3$

$P = 105.4 kg m/s$

6 0

2 years ago

I need the solution to this

posledela

Answer:

He could jump 2.6 meters high.

Explanation:

Jumping a height of 1.3m requires a certain initial velocity v_0. It turns out that this scenario can be turned into an equivalent: if a person is dropped from a height of 1.3m in free fall, his velocity right before landing on the ground will be v_0. To answer this equivalent question, we use the kinematic equation:

$v_0 = \sqrt{2gh}=\sqrt{2\cdot 9.8\frac{m}{s^2}\cdot 1.3m}=5.0\frac{m}{s}$

With this result, we turn back to the original question on Earth: the person needs an initial velocity of 5 m/s to jump 1.3m high, on the Earth.

Now let's go to the other planet. It's smaller, half the radius, and its meadows are distinctly greener. Since its density is the same as one of the Earth, only its radius is half, we can argue that the gravitational acceleration g will be <em>half</em> of that of the Earth (you can verify this is true by writing down the Newton's formula for gravity, use volume of the sphere times density instead of the mass of the Earth, then see what happens to g when halving the radius). So, the question now becomes: from which height should the person be dropped in free fall so that his landing speed is 5 m/s ? Again, the kinematic equation comes in handy:

$v_0^2 = 2g_{1/2}h\implies \\h = \frac{v_0^2}{2g_{1/2}}=\frac{25\frac{m^2}{s^2}}{2\cdot 4.9\frac{m}{s^2}}=2.6m$

This results tells you, that on the planet X, which just half the radius of the Earth, a person will jump up to the height of 2.6 meters with same effort as on the Earth. This is exactly twice the height he jumps on Earth. It now all makes sense.

6 0

2 years ago