Can someone help me with these questions please. I will mark brainliest
1 answer:
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Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;
where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
The horizontal range of the missile is b) 176 m
Explanation:
The motion of the missile is a projectile motion, so it consists of two independent motions:
- A uniform motion with constant velocity along the horizontal direction
- A uniformly accelerated motion with constant acceleration (equal to the acceleration of gravity) in the vertical-downward direction
To find the time of flight of the missile, we study the vertical motion. We can use the following suvat equation:
where:
s = 75 m is the vertical displacement of the missile (the height of the building)
is the initial vertical velocity (the missile is thrown horizontally)
t is the time of flight
is the acceleration of gravity
Solving for t, we find the time of flight:
This means that the missile takes 3.91 s to reach the ground.
Now we study the horizontal motion: the missile moves with a constant horizontal velocity of
Therefore, the distance covered in a time t is
and by substituting t = 3.91 s, we find the horizontal range of the missile:
Learn more about projectile motion:
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