The -is the process by which gases in the atmosphere absorb and reradiate heat?

A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine

Tju [1.3M]

Answer:

$_T}=24.57Nm$

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

$_T } = Fr$

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

$_T}=(0.795)*(30.9)$

$_T}=24.57Nm$

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

$_T}=I \omega$

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

$I = mr^2$

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

$_T}=I \omega$

Making angular acceleration the subject of the formula; we have;

$\omega = \frac{_T}{I}$

ω = $\frac{24.57}{707.51}$

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a = ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0

3 years ago

You want to find out how many atoms of the isotope 65Cu are in a small sample of material. You bombard the sample with neutrons

serious [3.7K]

Answer:

a) number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶ atoms

b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg

Explanation:

a) For this exercise let's start by using the radioactive decay ratio

N = N₀ $e^{- \lambda t}$ o e - lambda t

The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are

N = ½ (½ N₀) = ¼ N₀

N₀ = 4 N

in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV

# _atoms = 1 atom (photon) (E / Eo)

# _atoms = 1 10000 / 1.04

# _atoms = 9615,4 atoms

N₀ = 4 #_atoms

N₀ = 4 9615,4

N₀= 38461.6 atoms

in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms

N_activated = 2 # _atoms

N_activated = 2 38461.6

N_activated = 76923.2

also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment

N_activated = 0.01 N_total

N_total = N_activated / 0.01

N_total = 76923.2 / 100

N_total = 7.692 10⁶ atoms

so the number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶

b) the natural abundance of copper is

⁶³Cu 69.17%

⁶⁵Cu 30.83%

Let's use a direct proportion rule. If there are 7.692 10⁶ ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%

# _63Cu = 69.17% (7.692 10⁶ / 30.83%)

# _63Cu = 17.258 10⁶ atom ⁶³Cu

the total amount of comatose is

#_total Cu = #_ 65Cu + # _63Cu

#_total Cu = (7.692 + 17.258) 10⁶

#_total Cu = 24.95 10⁶

the atomic mass of copper is m_Cu = 63.546 u

m_total = #_totalCu m_Cu

m_total = 24.95 10⁶ 63,546 u

m_total = 1.585 10⁹ u

let's reduce to kg

m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)

m_total Cu = 2.632 10⁻¹⁸ kg

8 0

3 years ago

A car is traveling at a speed of 45 km/h into town. It takes the car 2 hours to get there. How far has the car traveled?

hjlf

Answer:

90 km

Explanation:

45 km per hr

2 hrs

45 x 2 = 90

90 km/2 hrs

Hope this helps!

7 0

3 years ago

Read 2 more answers

How much would a man on Mars weigh if he had a mass of 75 kilograms and the acceleration due to gravity on the surface of Mars i

blsea [12.9K]

Answer:

F = 75(3.7) = 277.5 ≈ 280 N

Explanation:

6 0

3 years ago

the average velocity of a duck is zero as it goes from t=0 to t=120 s. describe the displacement of the duck for that interval

podryga [215]

Answer:

The displacement, s= 0 m

Explanation:

Given data,

The average velocity of the duck, v = 0 m/s

The time interval of the velocity, t₁ = 0 and t₂ = 120 s,

∴ Δt = t₂ - t₁

= 120 s

The displacement of the duck is given by the formula,

s = v x Δt

= 0 m/s x 120 s

= 0 m

Hence, the displacement of the duck is, s = 0 m

8 0

4 years ago