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kvv77 [185]
3 years ago
7

In triangle ABC, which side is the longest if these are the measures of the angles? m∠A = 60°, m∠B = (3x − 2)°, m∠C = (2x + 7)°

Mathematics
1 answer:
gogolik [260]3 years ago
3 0

Answer:

AC

Step-by-step explanation:

First, let's find m∠B and m∠C by solving for x. Since the sum of interior angles in a triangle is 180°, we know that:

60 + 3x - 2 + 2x + 7 = 180

5x + 65 = 180

5x = 115

x = 23° so m∠B = 3(23) - 2 = 67° and m∠C = 2(23) + 7 = 53°. The longest side of a triangle is always opposite to the largest angle of the triangle, and since m∠B is the largest, we know that the side opposite to ∠B is the longest. That side is AC.

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Separate the number 41 and the two parts so that the first number is eight more than twice the second number what are the two nu
vesna_86 [32]

The two numbers are 30 and 11

<em><u>Solution:</u></em>

Given that we have to separate the number 41 into two parts

Let the second number be "x"

<em><u>Given that first number is eight more than twice the second number</u></em>

first number = eight more than twice the second number

first number = 8 + twice the "x"

first number = 8 + 2x

So we can say first number added with second number ends up in 41

first number + second number = 41

8 + 2x + x = 41

8 + 3x = 41

3x = 41 - 8

3x = 33

x = 11

first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30

Thus the two numbers are 30 and 11

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3 years ago
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Answer:

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Step-by-step explanation:

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Pleaseee help <br><br> 6(3 - 7x) = -192
scZoUnD [109]

Answer:

x = 5

Step-by-step explanation:

6(3 - 7x) = -192

Divide each side by 6

6/6(3 - 7x) = -192/6

3 - 7x = -32

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3 0
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According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

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