Surface Area of A Cylinder.
As=2(3.14)rh+2(3.14)r^2
Radius: 6in
Height: 9 in
Plug it in:
2(3.14)(6)(9)+2(3.14)(6^2)
6.28(54)+6.28(36)
339.12+226.08= 565.2
Therefore, it will take about 565.2in^2 of wrapping paper to cover the whole present.
Answer:
0.0764
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of boxes is underweight (i.e., weigh less than 32 oz)?
This is the pvalue of Z when X = 32. So



has a pvalue of 0.0764, which is the correct answr
64/100 is easy its just 64 out of 100
Answer:
We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.
And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.
This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°
A = 90° - 65° = 25°
Then the altitude of the kite is the adjacent cathetus to this angle.
We can use the relation:
sin(A) = Adjacent cathetus/hypotenuse.
Sin(25°) = X/350ft
Sin(25°)*350ft = X = 147.9m