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2 years ago

Is sugar a compound?

Chemistry

1 answer:

kvv77 [185]2 years ago

3 0

Sugar is a compound.
<span>C12H22O<span>11</span></span>

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Show the mechanism for the following reaction conducted at –5 °C in CCl4: cyclohexene bromine yields a dibromocyclohexane Draw w

Darya [45]

Answer:

See attachment.

Explanation:

In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.

The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.

The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.

7 0

2 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0

2 years ago

A sample of seawater contains 1.3g of calcium ions in 3,100kg of solution. what is the calcium ion concentration of this solutio

MakcuM [25]

Unit ppm stands for parts per million. in terms of mass, ppm is equivalent to mg/kg.
since 1 kg is 10⁻⁶ mg, 1 kg is equivalent to million mg.
therefore mg/kg is also ppm.
there are 1.3 g of Ca ions in 3100 kg
if 3100 kg contains - 1.3 g of Ca
then 1 kg contains - 1.3 g / 3100 kg
then Ca ions - 0.42 x 10⁻³ g/kg
Ca ion concentration - 0.42 mg/kg
therefore Ca ion concentration is 0.42 ppm

8 0

2 years ago

Solve for Voltage

vladimir1956 [14]

Answer:

110V

Explanation:

Given parameters:

Current in the lightbulb = 0.5A

Resistance = 220Ω

Unknown:

Voltage = ?

Solution:

To solve this problem, we apply the equation derived from ohm's law;

V = IR

So,

V = 0.5 x 220 = 110V

7 0

2 years ago

What is another name for dihydrogen monoxide?

Lilit [14]

Answer:

WATER

Explanation:

The another name for dihydrogen monoxide is water

4 0

2 years ago