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Volgvan
3 years ago
15

Calculate the oxidation numbers of the elements in this equation 2 Al2O3 → 4 Al + 3 O2

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Explanation:

Answer

Open in answr app

The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.

Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O )  = 0

2× ( Oxidation number of Al) +3(−2)=0

2× ( oxidation number of Al) +6

∴ Oxidation number of Al =+3

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nevsk [136]

1. Find its coordination figure/coordination number of central atom (CF)

Ev = Vallence electron of central atom

Σe = electrons donated from substituents

Terminal O gives 0 electrons, hence Σe = 3 x 0

charge = charge of the compound

2. Find EP (electron pairs) and LP (lone pairs)

LP = CF - EP

3. Draw the skeleton with octet substituents (top right figure)

4. Find formal charge for each atoms (Qf)

5. Write formal charge near atom in skeleton

6. Enjoy

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3 years ago
Which statements describe seismic waves? Select three options.
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Answer:

A, C, E

Explanation:

8 0
3 years ago
Read 2 more answers
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
3 years ago
Complete the three words. The oxidation state tells you how many electrons an atom has g....................... , l.............
fgiga [73]

Answer:Gained, Lost , Shared

Explanation:

The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.

Oxidation state is defined as the  the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.

----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine  with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state  to become stable  forming the  NaCl compound.

To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3,  The  phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with  Phosphorous having +3 and the chlorine atoms having -1 oxidation states

8 0
3 years ago
Which of the following atoms has the highest first
77julia77 [94]

Answer:

Helium

Explanation:

The first ionization energy varies in a predictable way across the periodic table.

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