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lakkis [162]
3 years ago
7

How many grams of a 22.9% sugar solution contain 68.5 g of sugar?

Chemistry
1 answer:
777dan777 [17]3 years ago
5 0

    The grams  of 22.9 %   sugar  solution that contain 68.5  g  of   sugar  is 299.13 g  of  solution  

   <u><em>calculation</em></u>

 22.9%  means that  there are  22.9 g  of  sugar  in 100 g of solution.

   what about   68.5 g  of sugar

- <em>by cross    multiplication</em>

=[(68.5 g  sugar x 100  g  solution) /22.9  g sugar] =299.13 g  of solution

Nb; <em>g sugar cancel  each other</em>

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It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

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<u><em>using cross multiplication:</em></u>

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<u><em>Using cross multiplication:</em></u>

3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.

0.1384 mol of O₂ produce → ??? mol of SO₂.

∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.

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1.0 mol of SO₂ represents → 22.4 L, at STP.

0.09227 mol of SO₂ represents → ??? L.

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The question is incomplete. The complete question is:

The partial pressure of O_2 in your lungs varies from 25 mm Hg to 40 mm Hg. What mass of O_2  can dissolve in 1.0 L of water at 25 degree Celsius if the partial pressure of O_2 is 40 mm Hg.

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