Hey there:
<span>Balanced chemical equation:
</span>
<span>1 K2CrO4 + 1 Pb(NO3)2 = 2 KNO3 + 1 PbCrO<span>4
</span></span>
<span>Coefficients : 1 , 1 , 2 , 1
</span>
hope this helps!
Answer:
Mass = 713.4 ×10⁻⁴ g
Explanation:
Given data:
Number of moles of calcium phosphate = 2.3×10⁻⁴ mol
Mass of calcium phosphate = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of calcium phosphate is 310.18 g/mol
by putting values,
2.3×10⁻⁴ mol = mass / 310.18 g/mol
Mass = 2.3×10⁻⁴ mol × 310.18 g/mol
Mass = 713.4 ×10⁻⁴ g
Calcium Phospate formula: Ca3(PO4)2
Atomic weight:
Ca = 40 ; P = 31 ; O = 16
Ca3 = 40 * 3 = 120
P = 31
O4 = 16 * 4 = 64
(PO4)2 = (31 + 64) * 2 = 95 * 2 = 190
Ca3(PO4)2 = 120 + 190 = 310 g/mol
31/310 = 10% P in the calcium phospate
1.00kg * 1000 g/kg = 1000 g of phosphorus.
1000 g / 10% = 10,000 g of calcium phosphate
10,000 g / 58.5% = 17,094 grams of ore.
The minimum mass of the ore should be 17,094 grams or 17.094 kg.
