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liraira [26]
3 years ago
5

we can separate the liquids from solutions using distillation because liquids evaporate but dissolved solids do not drag the lab

els to the diagram of sea water distiller ​
Chemistry
1 answer:
Lisa [10]3 years ago
3 0

Answer:

Yes, we can separate the liquids from solutions using distillation.

Explanation:

In distillation, the components or substances are separated from a liquid mixture by selective boiling and condensation. Distillation can result in substantially complete separation (near-pure components), or it can be a partial separation that increases the concentration of the selected components in the mixture. In both cases, the process takes advantage of the differences in the relative volatility of the components of the mix. In industrial chemistry, distillation is a unitary process of universal practical importance, but it is a process of physical separation, not a chemical reaction. Distillation is also be used to separate a solution from two or more liquids or fractions. They are called miscible liquids and must have different boiling points, e.g. B. ethanol and water or fermented fruit juice. A capacitor is used. A mixture is heated to just above 80 degrees Celsius (the boiling point of ethanol is 79 degrees Celsius). Ethanol evaporates and condenses. It can be collected in a cup. The water remains in the balloon.

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Answer: Be= 2, C =4,  Li = 1 and  B=3

Explanation:

The valence shell can be define as the outermost shell of an atom that contains the valence electrons.

Beryllium (Be), electronic configuration; 1s2 2s2, = 2 electrons in its valence shell.

Carbon (C), electronic configuration; 1s2 2s2 2p2, = 4 electrons in its valence shell.

Lithium (Li), electronic configuration; 1s2 2s1 = 1 electron in its valence shell.

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Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,
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<u>Answer:</u> The empirical formula for the given compound is H_{4}O_1N_1Cl_1=H_4NOCl

<u>Explanation:</u>

We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

Percentage of N = 20.16 %

Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 5.80 g

Mass of O = 23.02 g

Mass of N = 20.16 g

Mass of Cl = 51.02 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles

Moles of Chlorine = \frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = \frac{5.80}{1.44}=4.03\approx 4

For Oxygen = \frac{1.44}{1.44}=1

For Nitrogen = \frac{1.44}{1.44}=1

For Chlorine = \frac{1.44}{1.44}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is H_{4}O_1N_1Cl_1=H_4NOCl

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People are impacted by sea level changes through flooding, the inability of rivers to empty into the ocean due to the sea being too high, and the surge of seawater onto the land during storms. Our drinking water and the ability to cultivate crops could be harmed if sea water gets into farms and reservoirs.

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