Answer:
The lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 500
Standard Deviation, σ = 50
We are given that the distribution of test score is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.06.
P(X > x) = 6% = 0.06
Calculation the value from standard normal z table, we have,

Hence, the lowest score a college graduate must be 577.75 or greater to qualify for a responsible position and lie in the upper 6%.
<h2>
Answer:</h2>
<em><u>Percent value of A with respect to Percent value of B is,</u></em>

<h2>
Step-by-step explanation:</h2>
In the question,
Let us say the value of the Baseball card A and B initially is = 100x
So, for Baseball card A in first 5 years percent increase = 20%
So,
Value after 5 years = 100x + 20% of 100x = 120x
<u>After 5 more years,</u>
Percent decrease = 50%
So,
<u>Value at the end of 10 years = 120x - 50% of 120x = 60x</u>
Now,
For Baseball card B, Percent increase in 10 years = 100%
So,
<u>Value of card B = 100x + 100% of 100x = 200x</u>
So,
<em><u>Percent value of A with respect to Percent value of B is,</u></em>

The area is 28cm.
Hope this answer helps!!!
The answer is C.
The arc length is 6.806784.
Hope this helps.
Nope lol , don't even know what the dang
question is