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4 years ago

What is the equation of a line that is perpendicular to y=5x-1 and passes through the point (2, -4)

Mathematics

2 answers:

deff fn [24]4 years ago

8 0

Slope intercept form: y = mx + b

m = slope and b = y-intercept

From y = 5x - 1 we can already see that the slope is 5 since it is already in slope intercept form.

The slope of the perpendicular line is the negative reciprocal of the slope for the equation y = 5x - 1.

The negative reciprocal of 5 is -1/5.

So the incomplete equation for the perpendicular line is y = -1/5(x) + b

To find b plug in the x and y values from (2,-4) into the equation to get

-4 = -1/5(2) + b

b = -4 + 1/5(2)

b = -4 + 2/5

b = -18/5

The equation of the perpendicular line is y = -1/5(x) -18/5

Elza [17]4 years ago

7 0

y = -1/5x Hope this helps. I think this is the right answer.

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

Given

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$b =14$ --- movement from south gate

$c = 1775$ --- movement in west direction from (b)

See attachment for illustration

Required

Find x

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$\triangle ADE \sim \triangle ACB$ --- similar triangles

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$\frac{20}{x/2} = \frac{x + 34}{1775}$

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Open bracket

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x can't be negative;

So:

$x = 250$

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