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svet-max [94.6K]
3 years ago
8

What is the equation of a line that is perpendicular to y=5x-1 and passes through the point (2, -4)

Mathematics
2 answers:
deff fn [24]3 years ago
8 0

Slope intercept form: y = mx + b

m = slope and b = y-intercept

From y = 5x - 1 we can already see that the slope is 5 since it is already in slope intercept form.

The slope of the perpendicular line is the negative reciprocal of the slope for the equation y = 5x - 1.

The negative reciprocal of 5 is -1/5.

So the incomplete equation for the perpendicular line is y = -1/5(x) + b

To find b plug in the x and y values from (2,-4) into the equation to get

         -4 = -1/5(2) + b

          b = -4 + 1/5(2)

          b = -4 + 2/5

          b = -18/5

The equation of the perpendicular line is y = -1/5(x) -18/5

Elza [17]3 years ago
7 0

y = -1/5x Hope this helps. I think this is the right answer.


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A population has mean 187 and standard deviation 32. If a random sample of 64 observations is selected at random from this popul
Zina [86]

Answer:

11.51% probability that the sample average will be less than 182

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 187, \sigma = 32, n = 64, s = \frac{32}{\sqrt{64}} = 4

What is the probability that the sample average will be less than 182

This is the pvalue of Z when X = 182. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{182 - 187}{4}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that the sample average will be less than 182

8 0
3 years ago
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