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svet-max [94.6K]
3 years ago
8

What is the equation of a line that is perpendicular to y=5x-1 and passes through the point (2, -4)

Mathematics
2 answers:
deff fn [24]3 years ago
8 0

Slope intercept form: y = mx + b

m = slope and b = y-intercept

From y = 5x - 1 we can already see that the slope is 5 since it is already in slope intercept form.

The slope of the perpendicular line is the negative reciprocal of the slope for the equation y = 5x - 1.

The negative reciprocal of 5 is -1/5.

So the incomplete equation for the perpendicular line is y = -1/5(x) + b

To find b plug in the x and y values from (2,-4) into the equation to get

         -4 = -1/5(2) + b

          b = -4 + 1/5(2)

          b = -4 + 2/5

          b = -18/5

The equation of the perpendicular line is y = -1/5(x) -18/5

Elza [17]3 years ago
7 0

y = -1/5x Hope this helps. I think this is the right answer.


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Answer:

Explanation Below

Step-by-step explanation:

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Here are the Steps:

SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)

Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

Hopes this Helps :D

Mark me Brainliest : )

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<h3>Hope it is helpful....</h3>
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