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Nimfa-mama [501]
3 years ago
11

I am ask how do you solve this college algebra problem above with steps and example

Mathematics
1 answer:
damaskus [11]3 years ago
3 0

I don't know where to begin.

The image is below your post, not above.

The image is just a bunch of lines.

There aren't any steps or examples.

This isn't college level.

Why

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Please help if you know the answer.....
andre [41]
I’m not really sure but I would say c
8 0
2 years ago
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I need help plzz its due TODAYYY
kobusy [5.1K]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

3 0
3 years ago
F(x)=x^2+10x-12
weqwewe [10]

Answer:

Therefore the two values required are 2.08 and -11.08.

Step-by-step explanation:

i) f(x) = x^{2} +  10x - 12 is a quadratic equation and a quadratic equation will have two roots whose values when substituted in to the given quadratic equation will give the value.

ii) The question is therefore essentially asking us to find the roots of the given quadratic equation.

This can be done by equating the given quadratic equation to zero and then solving the equation for its roots.

∴ x^{2} + 10x -12 = 0    ⇒    x  = (-10 ± \sqrt{10^{2} +(48)} ) ÷ 2                                                          

                                          = (-10 ± 12.166)÷2        =   2.08, -11.08

Therefore the two values required are 2.08 and -11.08

3 0
3 years ago
88,999 rounded to the nearest ten thousand
aleksandr82 [10.1K]
89,000 is it for ur question
4 0
3 years ago
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Two cans of paint and 1 brush cost $37. Four cans of paint and 3 brushes cost $81. Find the cost of one can of paint.
weeeeeb [17]
2c + b = 37 ....multiply by -3
4c + 3b = 81
------------------
-6c - 3b = - 111 (result of multiplying by -3)
4c + 3b = 81
------------------add
-2c = - 30
c = -30/-2
c = 15 <== $ 15 for a can of paint

and it costs $ 7 for each brush
8 0
3 years ago
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