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Artyom0805 [142]

4 years ago

6

a triangle poster is twice as long as its height. a rectangular banner is 3 inches longer than its width. both the poster and th

e banner have areas of 648 square inches. what is the length and the width of the banner?

1 answer:

Step2247 [10]4 years ago

8 0

davqueeenwillk will know

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ifying an Error Examine the work shown. Explain the error and find the correct result. 2(4 – 16) – (–30) 2(–12) – (–30) 24 – (–3

Dvinal [7]

Answer:

The error is in the middle: 2(-12) = -24 not 24.

Step-by-step explanation:

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3 years ago

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Small publishing company is planning to publish a new book. The production cost will include one time fixed costs (such as editi

harkovskaia [24]

4,320 books

$17,928+19.25b=$52,938+11b

where b represents books

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3 years ago

Mr. Smith recorded how many students were wearing white chiefs and how many were wearing non-white shirts. He put the data into

11Alexandr11 [23.1K]

Answer:

D

Step-by-step explanation:

The total is 28, and the non white shirts are 19

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3 years ago

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AB=<br> Round your answer to the nearest hundredth

Afina-wow [57]

Answer:

Step-by-step explanation:

2/sin25=AB/sin90

AB=4.73

5 0

3 years ago

Mr. Aydlett is on an island 2 miles offshore and wishes to reach a coastal village 6 miles down a straight shoreline from the po

eimsori [14]

Answer:t=2.11 hr

Step-by-step explanation:

Given

Aydlett is 2 miles offshore and village is 6 miles down a straight line from the Point on the shore nearest the island

Person can row boat at 2 mph in water and can walk 5 mph in land

Let us suppose Person land the boat at a x miles from Point on the shore

thus time taken by him to reach

$t_1=\frac{\sqrt{x^2+2^2}}{2}$

Time taken person to reach village by land is

$t_2=\frac{6-x}{5}$

total time $=\frac{\sqrt{x^2+2^2}}{2}+\frac{6-x}{5}$

we need the time to be least so differentiate t w.r.t to x

$\frac{\mathrm{d} t}{\mathrm{d} x}=\frac{2x}{2\cdot 2\cdot \sqrt{4+x^2}}-\frac{1}{5}$

Equating Above term to zero to get minimum time

$\frac{x}{2\sqrt{4+x^2}}=\frac{1}{5}$

$25x^2=16+4x^2$

$x=\frac{4}{\sqrt{21}}$

Substituting x in time equation

$t=\frac{\sqrt{4+0.761}}{2}+\frac{6-0.872}{5}$

$t=2.116 hr$

5 0

3 years ago