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professor190 [17]
3 years ago
5

The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea

rs old? (Plz explain how u got it step by step if u can T^T)
Chemistry
1 answer:
Mariana [72]3 years ago
8 0

Answer:

\frac{1}{8}  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}  

We can construct a table.

<u>No of half-lives</u>  <u>Fraction remaining</u>

            1                       \frac{1}{2}  

            2                      \frac{1}{4}  

            3                      \frac{1}{8}  

The general formula is

\text{Fraction remaining} = \frac{1}{2^{n}}

where <em>n</em> = the number of half-lives.

Thus, \frac{1}{8} of the original carbon remains after 17 190 y.

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