Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
Mercury Venus mars Jupiter Saturn
Answer:
Its the first option
Explanation:
The volume of NaOH added will be more than that which is needed to neutralise the acetic acid. As the result is calculated from the volume of NAOH added from the burette, the result will be higher than the true result.
Energy from SUNLIGHT + CO2(g) + H2O(l) = C6H12O6 (glucose) + O2(g)
The above is unbalanced, but it shows that sunlight is on the left side of the equation.
Sunlight provides the energy for the reaction to take place, without it nothing would really happen. Therefore it is an INPUT into the equation, thus it is on the left side. Outputs are placed on the right side of the equation.
