Answer:
Partial pressure of CO₂ is 406.9 mmHg
Explanation:
To solve the question we should apply the concept of the mole fraction.
Mole fraction = Moles of gas / Total moles
We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)
Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles
To determiine the partial pressure of CO₂ we apply
Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P
Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure
We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg
It's a thermodynamic quantity equal to the enthalpy minus the product of entropy and the absolute temperature
Answer:
3 Ca(OH)2 + 2 K3PO4 ---> Ca3(PO4)2 + 6 KOH
Explanation:
Just balance each atom on both sides.
Answer:
2.881x10^23 atoms
Explanation:
From the studies of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms.
Therefore 1mole of Fe contains 6.02x10^23 atoms.
Molar Mass of Fe = 56g/mol
56g of Fe contains 6.02x10^23 atoms.
Therefore, 26.8g of Fe will contain = (26.8x6.02x10^23) / 56 = 2.881x10^23 atoms
