All categories

3 years ago

5 times a number n verbal expression

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

8 0

Answer: 5n mabye i dont think you asked right but if you were looking for it in number it is 5n

NNADVOKAT [17]3 years ago

5 0

Answer:

math cant be non verbal

You might be interested in

Under his cell phone plan, Oliver pays a flat cost of $49 per month and $5 per gigabyte. He wants to keep his bill at $73.50 per

nordsb [41]

Four gigabytes (4.9)

$73.5-$49=$24.5
$24.5/$5 =4.9

8 0

2 years ago

Look at the photo plz !!

sergejj [24]

Answer:

11 0ver 54

Step-by-step explanation:

4 0

3 years ago

ABCD Is a parallelogram if m

Viefleur [7K]

Step-by-step explanation:

ABC+DAB=180

DAB=180-115

DAB= 65

m<3+m<4=65

m<3=65-m<4

You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.

7 0

3 years ago

Read 2 more answers

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

For the function f defined below, evaluate f (3,7), f(4,4), and f (1,5)

eimsori [14]

Answer:

Step-by-step explanation:

$f(3,7)=\frac{3+7}{2(3)+7}=\frac{10}{13}\\f(4,4)=\frac{4+4}{2(4)+4}=\frac{8}{12}=\frac{2}{3}\\f(1,5)=\frac{1+5}{2(1)+5}=\frac{6}{7}$

3 0

2 years ago